每日一题 2019.9.23

# coding=utf-8
"""
有一分数序列：2/1，3/2，5/3，8/5，13/8，21/13...求出这个数列的前20项之和.
"""

fenZi1 = 2
fenZi2 = 3
fenZi = []
fenMu1 = 1
fenMu2 = 2
fenMu = []
fenZi.append(fenZi1)
fenZi.append(fenZi2)
fenMu.append(fenMu1)
fenMu.append(fenMu2)

def getFenZi(n, num1, num2):
    if n + 2 < 20:
        n += 1
        num1, num2 = num2, num1 + num2
        fenZi.append(num2)
        getFenZi(n, num1, num2)
    else:
        print("fenzi ok !")

def getFenMu(n, num1, num2):
    if n + 2 < 20:
        n += 1
        num1, num2 = num2, num1 + num2
        fenMu.append(num2)
        # print(num2)
        getFenMu(n, num1, num2)
    else:
        print("fenmu ok")


def sumNum(num1, num2):
    num = []
    sum = 0
    for i in range(20):
        num.append(num1[i]/num2[i])
    print(num)
    for j in range(20):
        sum += num[j]
    return sum



if __name__ == '__main__':
    getFenZi(0, fenZi1, fenZi2)
    getFenMu(0, fenMu1, fenMu2)
    print(fenZi)
    print(fenMu)
    sum = sumNum(fenZi,fenMu)
    print(sum)

# 写太麻烦了 主要目的是想练习一下函数
# 初学Python 如有不足 请多多指教

标签：20,num1,num2,23,每日,fenMu,print,append,2019.9
来源： https://www.cnblogs.com/walxt/p/11574761.html