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Js实现的俄罗斯方块小游戏------Sestid

2019-09-21 14:08:34 作者：互联网

详细代码：

<!DOCTYPE html>
<html>
	<head>
		<meta charset="UTF-8">
		<title>俄罗斯方块</title>
	</head>
	<body>
		<div id = "box"
             style = "margin : 20px auto;
             text-align : center;
             width : 252px;
             font : 25px / 25px 宋体;
             background : #000;
             color : #9f9;
             border : #999 20px ridge;
             text-shadow : 2px 3px 1px #0f0;">
             </div>
		
		<script>
			var map=eval("["+Array(23).join("0x801,")+"0xfff]");
			var tatris=[[0x6600],[0x2222,0xf00],[0xc600,0x2640],[0x6c00,0x4620],[0x4460,0x2e0,0x6220,0x740],[0x2260,0xe20,0x6440,0x4700],[0x2620,0x720,0x2320,0x2700]];
            var keycom={"38":"rotate(1)","40":"down()","37":"move(2,1)","39":"move(0.5,-1)"};
            var dia, pos, bak, run;
            function start(){
            dia=tatris[~~(Math.random()*7)];
            bak=pos={fk:[],y:0,x:4,s:~~(Math.random()*4)};
            rotate(0);
            }
            
            function over(){
			document.onkeydown=null;
			clearInterval(run);
			alert("GAME OVER");
			}
            
            function update(t){
            	bak={fk:pos.fk.slice(0),y:pos.y,x:pos.x,s:pos.s};
				if(t) return;
				for(var i=0,a2=""; i<22; i++)
				a2+=map[i].toString(2).slice(1,-1)+"<br/>";
				for(var i=0,n; i<4; i++)
				if(/([^0]+)/.test(bak.fk[i].toString(2).replace(/1/g,"\u25a1")))
				 a2=a2.substr(0,n=(bak.y+i+1)*15-RegExp.$_.length-4)+RegExp.$1+a2.slice(n+RegExp.$1.length);
				 document.getElementById("box").innerHTML=a2.replace(/1/g,"\u25a0").replace(/0/g,"\u3000");
				 
			}
            
            function is(){
            	 for(var i=0; i<4; i++)
            	  if((pos.fk[i]&map[pos.y+i])!=0) return pos=bak;
            	 }
            function rotate(r){
            var f=dia[pos.s=(pos.s+r)%dia.length];
            for(var i=0; i<4; i++)
            pos.fk[i]=(f>>(12-i*4)&15)<<pos.x;
            update(is());
            }
            function down(){
            	 ++pos.y;
            	  if(is()){
            	  	for(var i=0; i<4 && pos.y+i<22; i++)
            	  	if((map[pos.y+i]|=pos.fk[i])==0xfff)
            	  	map.splice(pos.y+i,1), map.unshift(0x801);
            	  	 if(map[1]!=0x801) return over();
            	  	 start();
            	  	}
            	  update();
            	 }
            
            function move(t,k){
            	pos.x+=k;
            	 for(var i=0; i<4; i++)
            	 pos.fk[i]*=t;
            	 update(is());
            	}
            
            document.onkeydown=function(e){
             eval(keycom[(e?e:event).keyCode]);
            };
            start();
            run=setInterval("down()",400);
            
            
            
		</script>
		
	</body>
</html>

效果展示：

标签：function,move,pos,Js,小游戏,var,fk,Sestid,bak
来源： https://blog.csdn.net/Sestid/article/details/101104316