1147 Heaps (30 分)
作者:互联网
In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure))
Your job is to tell if a given complete binary tree is a heap.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers: M (≤ 100), the number of trees to be tested; and N (1 < N ≤ 1,000), the number of keys in each tree, respectively. Then M lines follow, each contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.
Output Specification:
For each given tree, print in a line Max Heap
if it is a max heap, or Min Heap
for a min heap, or Not Heap
if it is not a heap at all. Then in the next line print the tree's postorder traversal sequence. All the numbers are separated by a space, and there must no extra space at the beginning or the end of the line.
Sample Input:
3 8
98 72 86 60 65 12 23 50
8 38 25 58 52 82 70 60
10 28 15 12 34 9 8 56
Sample Output:
Max Heap
50 60 65 72 12 23 86 98
Min Heap
60 58 52 38 82 70 25 8
Not Heap
56 12 34 28 9 8 15 10
依然是堆的性质,再加一个后序遍历,这题30分有点多
1 #include <bits/stdc++.h> 2 3 using namespace std; 4 int an[1005]; 5 int n,m; 6 vector<int> v; 7 8 void predfs(int x){ 9 if(x*2 <= m) 10 predfs(x*2); 11 if(x*2+1 <= m) 12 predfs(x*2+1); 13 v.push_back(an[x]); 14 } 15 16 int main(){ 17 cin >> n >> m; 18 while(n--){ 19 v.clear(); 20 bool isbig = true, islittle = true; 21 for(int i = 1 ; i <= m ; ++i){ 22 cin >> an[i]; 23 if(i > 2){ 24 if(an[i/2] < an[i]) isbig = false; 25 if(an[i/2] > an[i]) islittle = false; 26 } 27 } 28 if(isbig) 29 puts("Max Heap"); 30 else if(islittle) 31 puts("Min Heap"); 32 else 33 puts("Not Heap"); 34 predfs(1); 35 for(int i = 0 ; i < v.size(); ++i) 36 printf("%d%c",v[i], i == v.size()-1? '\n':' '); 37 } 38 39 return 0; 40 }
标签:Heaps,1147,int,30,tree,60,heap,Heap 来源: https://www.cnblogs.com/zllwxm123/p/11273937.html