Leetcode 16: 3Sum Closest
作者:互联网
class Solution:
def threeSumClosest(self, nums: List[int], target: int) -> int:
res=0
temp=float('inf')
nums.sort()
n=len(nums)
#[-3, 0, 1, 2]
for i in range(n-2):
l, r= i+1, n-1
while l<r:
s=nums[i]+nums[l]+nums[r]
if s==target:
return s
if s<target:
if temp>abs(target-s):
temp=abs(target-s)
res=s; l+=1
elif temp<=abs(target-s):
l+=1
while l<r and nums[l-1]==nums[l]:
l+=1
elif s>target:
if temp>abs(target-s):
temp=abs(target-s)
res=s; r-=1
elif temp<=abs(target-s):
r-=1
while l<r and nums[r]==nums[r+1]:
r-=1
return res
标签:Closest,temp,nums,3Sum,res,int,abs,Leetcode,target 来源: https://blog.csdn.net/qq_39012149/article/details/96187995