2460: [BeiJing2011]元素
作者:互联网
总结:线性基插入;
https://www.lydsy.com/JudgeOnline/problem.php?id=2460
#include<bits/stdc++.h>
using namespace std;
#define sfi(i) scanf("%d",&i)
#define sfs(i) scanf("%s",(i))
#define pri(i) printf("%d\n",i)
#define sff(i) scanf("%lf",&i)
#define ll long long
#define ull unsigned long long
#define mem(x,y) memset(x,y,sizeof(x))
#define INF 0x3f3f3f3f
#define eps 1e-8
#define PI acos(-1.0)
#define lowbit(x) ((x)&(-x))
#define zero(x) (((x)>0?(x):-(x))<eps)
#define fl() printf("flag\n")
#define MOD(x) ((x%mod)+mod)%mod
#define endl '\n'
#define pb push_back
#define FAST_IO ios::sync_with_stdio(false);cin.tie(0);cout.tie(0)
//----------------------------------------------------------
const int BufferSize = 1 << 16;
char buffer[BufferSize], *head, *tail;
inline char Getchar() {
if (head == tail) {
int l = fread(buffer, 1, BufferSize, stdin);
tail = (head = buffer) + l;
}
return *head++;
}
inline ll read() {
ll x = 0, f = 1;char c = Getchar();
for (;!isdigit(c);c = Getchar()) if (c == '-') f = -1;
for (;isdigit(c);c = Getchar()) x = x * 10 + c - '0';
return x * f;
}
//----------------------------------------------------------
const int maxn=1e5+9;
struct node
{
ll id,val;
bool operator < (const node &b)const
{
return val>b.val;
}
}a[maxn];
ll p[100];
int main()
{
//FAST_IO;
//freopen("input.txt","r",stdin);
int n;
cin>>n;
for(int i=1;i<=n;i++)
{
cin>>a[i].id>>a[i].val;
}
sort(a+1,a+n+1);
ll ans=0;
for(int i=1;i<=n;i++)
{
for(int j=62;j>=0;j--)
{
if(!(a[i].id>>j)) continue;
if(!p[j])
{
p[j]=a[i].id;
break;
}
a[i].id^=p[j];
}
if(a[i].id) ans+=a[i].val;
}
cout<<ans<<endl;
//1 for(int i=62;i>=0;i--) if((ans^p[i])>ans) ans=ans^p[i];//从线性基中得到最大值
return 0;
}
标签:2460,val,int,元素,long,ans,BeiJing2011,id,define 来源: https://blog.csdn.net/weixin_39132605/article/details/95902098