1123 Is It a Complete AVL Tree

首先是建立二叉平衡树,

然后是层序遍历,注意判断是否是完全树的条件:

当发现某个节点的孩子为空时,以后如果发现某个节点存在孩子,那么就不是完全二叉树. 

#include <iostream>
#include <queue>
using namespace std;
struct TreeNode{
    int val{};
    TreeNode* left{};
    TreeNode* right{};
    int height=0;
};
int Height(TreeNode* root){
    if(root== nullptr){
        return -1;
    }
    return root->height;
}
TreeNode* rightRotate(TreeNode *root){
    TreeNode* L=root->left;
    root->left=L->right;
    L->right=root;
    root->height=max(Height(root->left),Height(root->right))+1;
    L->height=max(Height(L->left),Height(L->right))+1;
    return L;
}
TreeNode* leftRotate(TreeNode *root){
    TreeNode* R=root->right;
    root->right=R->left;
    R->left=root;
    root->height=max(Height(root->left),Height(root->right))+1;
    R->height=max(Height(R->left),Height(R->right))+1;
    return R;
}
TreeNode* leftRightRotate(TreeNode *root){
    root->left= leftRotate(root->left);
    return rightRotate(root);
}
TreeNode* rightLeftRotate(TreeNode *root){
    root->right= rightRotate(root->right);
    return leftRotate(root);
}
TreeNode* constructTree(TreeNode* root,int val){
    if(root==nullptr){
        root=new TreeNode();
        root->val=val;
        return root;
    }
    if(val<root->val){
        root->left=constructTree(root->left,val);
    } else{
        root->right=constructTree(root->right,val);
    }
    if(Height(root->left)-Height(root->right)==2){
        if(val<root->left->val){
            root= rightRotate(root);
        } else{
            root= leftRightRotate(root);
        }
    }
    if(Height(root->right)-Height(root->left)==2){
        if(val>root->right->val){
            root= leftRotate(root);
        } else{
            root= rightLeftRotate(root);
        }
    }
    //更新根节点的高度信息
    root->height=max(Height(root->left),Height(root->right))+1;
    return root;
}
bool isComplete=true;
//如果发现存在有为空孩子的节点,继续遍历过程中仍然发现存在有孩子不为空的节点,那么就不是一个完全二叉树
vector<int> levelOrder(TreeNode* root){
    queue<TreeNode* > queue1;
    vector<int> res;
    queue1.push(root);
    bool hasNull=false;
    while(!queue1.empty()){
        auto node=queue1.front();
        res.push_back(node->val);
        queue1.pop();
        if(node->left== nullptr){
            hasNull= true;
        } else{
            if(hasNull) {
                isComplete = false;
            }
                queue1.push(node->left);
        }
        if(node->right== nullptr){
            hasNull= true;
        } else{
            if(hasNull){
                isComplete= false;
            }
//            res.push_back(node->val);
            queue1.push(node->right);
        }
    }
    return res;
}
int main() {
    int N;
    cin>>N;
    TreeNode* root= nullptr;
    for (int i = 0; i < N; ++i) {
        int val;
        cin>>val;
        root=constructTree(root,val);
    }
    auto res=levelOrder(root);
    cout<<res[0];
    for (int i = 1; i < res.size(); ++i) {
        cout<<" "<<res[i];
    }
    cout<<endl;
    if(isComplete){
        cout<<"YES"<<endl;
    } else{
        cout<<"NO"<<endl;
    }
    return 0;
}

标签：right,TreeNode,val,1123,Tree,Height,AVL,root,left
来源： https://blog.csdn.net/weixin_42379312/article/details/94868336