Spring控制器不接受application / json
作者:互联网
当我从Chrome Rest Client传递application / json参数时,我收到400错误请求错误.
当我为@RequestParam添加required = false时,Controller接受请求,但值为Null.
@RequestMapping(value = "/add",
method = RequestMethod.POST,
consumes="application/json",
produces="application/json")
public @ResponseBody String add(
@RequestParam(value="surveyName") String surveyName,
@RequestParam(value="surveyDesc") String surveyDesc,
ModelMap model) throws Exception
{
System.out.println("request parameters in /add/syrvey surveyName= "+surveyName);
}
我的JSON请求如下,Content-Type是“aplication / json”
{"surveyName"="sd", "surveyDesc":"sd"}
我尝试使用headers =“Accept = application / json”,但它没有多大帮助.
我的调度程序 – servlet是
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation=">
<context:annotation-config />
<context:component-scan base-package="com.survey.controller" />
<context:component-scan base-package="com.survey.service" />
<context:component-scan base-package="com.survey.dao" />
<context:component-scan base-package="com.survey.entity" />
<context:component-scan base-package="com.survey.constants" />
<mvc:annotation-driven />
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
<bean id="jacksonMessageConverter" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter" />
<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
<property name="messageConverters">
<list>
<ref bean="jacksonMessageConverter" />
</list>
</property>
</bean>
</beans>
我的pom.xml是
<dependency>
<groupId>org.codehaus.jackson</groupId>
<artifactId>jackson-mapper-asl</artifactId>
<version>1.9.12</version>
</dependency>
任何帮助非常感谢
解决方法:
在您的情况下,您可以使用地图:
public @ResponseBody String add(@RequestBody Map<String, String> input) throws Exception
然后迭代它以找到您的参数,或者您可以使用Pojo
public class Pojo {
private String surveyName;
private String surveyDesc;
...
}
public @ResponseBody String add(@RequestBody Pojo pojo) throws Exception
希望这可能有用!
标签:spring-mvc,spring,http-status-code-404,rest-client 来源: https://codeday.me/bug/20190624/1279106.html