习题6-2 使用函数求特殊a串数列和

 1 #include <stdio.h>
 2 
 3 int fn(int a, int n);
 4 int SumA(int a, int n);
 5 
 6 int main()
 7 {
 8     int a, n;
 9 
10     scanf_s("%d %d", &a, &n);
11     printf("fn(%d, %d) = %d\n", a, n, fn(a, n));
12     printf("s = %d\n", SumA(a, n));
13 
14     return 0;
15 }
16 
17 /* 你的代码将被嵌在这里 */
18 int fn(int a, int n)
19 {
20     int number = 0;
21     for (int i = 0; i < n; i++)
22     {
23         number = number * 10 + a;
24     }
25     
26     return number;
27 }
28 
29 int SumA(int a, int n)
30 {
31     int sum = 0;
32     for (int i = 1; i <= n; i++)
33     {
34         sum = sum + fn(a, i);
35     }
36     
37     return sum;
38 }

标签：return,数列,int,number,SumA,printf,习题,fn,函数
来源： https://www.cnblogs.com/2018jason/p/10962150.html