LeetCode 232. Implement Queue using Stacks
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解答[Java]
import java.util.ArrayDeque;
import java.util.Deque;
class MyQueue {
Deque<Integer> stack1;
Deque<Integer> stack2;
/** Initialize your data structure here. */
public MyQueue() {
stack1 = new ArrayDeque<>();
stack2 = new ArrayDeque<>();
}
/** Push element x to the back of queue. */
public void push(int x) {
stack1.push(x);
}
/** Removes the element from in front of queue and returns that element. */
public int pop() {
if (!stack2.isEmpty()) {
return stack2.pop();
} else {
while (!stack1.isEmpty()) {
stack2.push(stack1.pop());
}
return stack2.pop();
}
}
/** Get the front element. */
public int peek() {
if (!stack2.isEmpty()) {
return stack2.peek();
} else {
while (!stack1.isEmpty()) {
stack2.push(stack1.pop());
}
return stack2.peek();
}
}
/** Returns whether the queue is empty. */
public boolean empty() {
if (stack1.isEmpty() && stack2.isEmpty()) {
return true;
} else {
return false;
}
}
}
/**
* Your MyQueue object will be instantiated and called as such:
* MyQueue obj = new MyQueue();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.peek();
* boolean param_4 = obj.isEmpty();
*/
标签:return,int,pop,Queue,isEmpty,using,stack2,Stacks,stack1 来源: https://blog.csdn.net/ligaopeng001/article/details/90178605