Problem A: 平面上的点——Point类 (III)

Description
在数学上，平面直角坐标系上的点用X轴和Y轴上的两个坐标值唯一确定。现在我们封装一个“Point类”来实现平面上的点的操作。

根据“append.cc”，完成Point类的构造方法和show()方法，输出各Point对象的构造和析构次序。实现showPoint()函数。

接口描述：
showPoint()函数按输出格式输出Point对象，调用Point::show()方法实现。
Point::show()方法：按输出格式输出Point对象。

Input
输入多行，每行为一组坐标“x,y”，表示点的x坐标和y坐标，x和y的值都在double数据范围内。

Output
输出每个Point对象的构造和析构行为。showPoint()函数用来输出（通过参数传入的）Point对象的值：X坐标在前，Y坐标在后，Y坐标前面多输出一个空格。每个坐标的输出精度为最长16位。输出格式见sample。

C语言的输入输出被禁用。

Sample Input
1,23,32,1
Sample Output
Point : (0, 0) is created.Point : (1, 2) is created.Point : (1, 2) is copied.Point : (1, 2)Point : (1, 2) is erased.Point : (1, 2) is erased.Point : (3, 3) is created.Point : (3, 3) is copied.Point : (3, 3)Point : (3, 3) is erased.Point : (3, 3) is erased.Point : (2, 1) is created.Point : (2, 1) is copied.Point : (2, 1)Point : (2, 1) is erased.Point : (2, 1) is erased.Point : (0, 0) is copied.Point : (1, 1) is created.Point : (0, 0) is copied.Point : (1, 1) is copied.Point : (0, 0) is copied.Point : (0, 0)Point : (1, 1)Point : (0, 0)Point : (0, 0) is erased.Point : (1, 1) is erased.Point : (0, 0) is erased.Point : (1, 1) is erased.Point : (0, 0) is erased.Point : (0, 0) is erased.
HINT
思考构造函数、拷贝构造函数、析构函数的调用时机。

#include <iostream>
#include<iomanip>
using namespace std;
class Point
{
private:
    double x,y;
public:
    Point ()
    {
        x=0;
        y=0;
        cout<<setprecision(16)<<"Point : (0, 0) is created."<<endl;
    }
    Point (double a ,double b )
    {
        x = a;
        y = b;
        cout<<setprecision(16)<<"Point : ("<<x<<", "<<y<<")is created."<<endl;
    }
    Point(double a)
    {
        x=a;
        y=a;
        cout<<setprecision(16)<<"Point : ("<<x<<", "<<y<<")is created."<<endl;

    }
  Point(Point const &p)
  {
      x=p.x;
      y=p.y;
      cout<<setprecision(16)<<"Point : ("<<x<<", "<<y<<")is  copied."<<endl;
  }
    void show()
   {
        cout<<setprecision(16)<<"Point : ("<<x<<", "<<y<<")"<<endl;
   }
    //~Point();
      ~Point ()
  {
      cout<<setprecision(16)<<"Point : ("<<x<<", "<<y<<")is  erased."<<endl;
  }
};
void showPoint(Point p)
{
    p.show();
}
void showPoint(Point q1,Point q2,Point q)
{
    q1.show();
    q2.show();
    q.show();
}
int main()
{
    char c;
    double a, b;
    Point q;
    while(std::cin>>a>>c>>b)
    {
        Point p(a, b);
        showPoint(p);
    }
    Point q1(q), q2(1);
    showPoint(q1, q2, q);
}

标签：erased,输出,Point,created,Problem,III,copied,showPoint
来源： https://blog.csdn.net/weixin_43400733/article/details/89341378