[模板]非递归线段树(zkw的变异版本)
作者:互联网
类似于zkw,但空间只用两倍,zkw要4倍。
可以下传标记,打熟后很好码。
#include <set>
#include <cmath>
#include <cstdio>
#include <cstring>
#include <iostream>
#include <assert.h>
#include <algorithm>
using namespace std;
#define LL long long
#define debug(...) fprintf(stderr, __VA_ARGS__)
#define GO debug("GO\n")
inline int rint() {
register int x = 0, f = 1; register char c;
while (!isdigit(c = getchar())) if (c == '-') f = -1;
while (x = (x << 1) + (x << 3) + (c ^ 48), isdigit(c = getchar()));
return x * f;
}
template<typename T> inline void chkmin(T &a, T b) { a > b ? a = b : 0; }
template<typename T> inline void chkmax(T &a, T b) { a < b ? a = b : 0; }
const int maxN = 1e5 + 10;
int n, h, m;
LL sum[maxN * 2], tag[maxN * 2];
void build() {
for (h = 1; 1 << h < n; ++ h);//计算树高
for (int i = n + 1; i <= 2 * n; ++ i) sum[i] = rint();
for (int i = n; i >= 1; -- i) sum[i] = sum[i<<1] + sum[i<<1|1];
}
void add(int x, int val, int len) {
sum[x] += val * len;
if (x <= n) tag[x] += val;//如果不是是叶子才打标记
}
void pu(int x) {
int len = 1;
while (x > 1) len<<=1, x >>= 1, sum[x] = sum[x<<1] + sum[x<<1|1] + tag[x] * len;//从下往上,儿子的值不一定正确,需要累上标记
}
void pd(int x) {
for (int i = h, len = 1 << (h - 1); i > 0; -- i, len >>= 1) {//从上到下len初始为1<<(h-1)
int y = x >> i;
if (tag[y]) {//下传标记
add(y<<1, tag[y], len);
add(y<<1|1, tag[y], len);
tag[y] = 0;
}
}
}
void modify(int l, int r, int val) {
l += n, r += n;
int l0 = l, r0 = r;
for (int len = 1; l <= r; l = (l + 1) >> 1, r = (r - 1) >> 1, len <<= 1) {//从下往上,叶子节点len为1
if (l & 1) add(l, val, len);
if (r & 1 ^ 1) add(r, val, len);
}
pu(l0); pu(r0);//别忘了pushup
}
LL query(int l, int r) {
l += n, r += n;
pd(l); pd(r);//查询前要下传该区间标记
LL ans = 0;
for (; l <= r; l = (l + 1) >> 1, r = (r - 1) >> 1) {
if (l & 1) ans += sum[l];
if (r & 1 ^ 1) ans += sum[r];
}
return ans;
}
int main() {
#ifndef ONLINE_JUDGE
freopen("xhc.in", "r", stdin);
freopen("xhc.out", "w", stdout);
#endif
n = rint(), m = rint();
build();
int op, x, y, k;
while (m --) {
op = rint(), x = rint(), y = rint();
if (op == 1) {
k = rint();
modify(x, y, k);
} else {
printf("%lld\n", query(x, y));
}
}
}
标签:include,int,rint,线段,len,zkw,sum,模板 来源: https://www.cnblogs.com/HNYLMSTea/p/10587028.html