校园内的汽车
作者:互联网
https://www.acwing.com/problem/content/description/1587/
思路:
电话记录的模型,先筛选出所有符合要求的记录,之后按照题目要求做即可。
#include <iostream>
#include <cstring>
#include <algorithm>
#include <unordered_map>
#include <vector>
using namespace std;
struct Event
{
int tm, status;
bool operator< (const Event &t) const
{
return tm < t.tm;
}
};
int get(vector<Event>& ets)
{
int res = 0;
for (int i = 0; i < ets.size(); i += 2)
res += ets[i + 1].tm - ets[i].tm;
return res;
}
int main()
{
int n, m;
scanf("%d%d", &n, &m);
unordered_map<string, vector<Event>> cars;
char id[10], status[10];
for (int i = 0; i < n; i ++ )
{
int hh, mm, ss;
scanf("%s %d:%d:%d %s", id, &hh, &mm, &ss, status);
int t = hh * 3600 + mm * 60 + ss;
int s = 0;
if (status[0] == 'o') s = 1;
cars[id].push_back({t, s});
}
vector<Event> events;
for (auto& item : cars)
{
auto& ets = item.second;
sort(ets.begin(), ets.end());
int k = 0;
for (int i = 0; i < ets.size(); i ++ )
if (ets[i].status == 0)
{
if (i + 1 < ets.size() && ets[i + 1].status == 1)
{
ets[k ++ ] = ets[i];
ets[k ++ ] = ets[i + 1];
i ++ ;
}
}
ets.erase(ets.begin() + k, ets.end());
for (int i = 0; i < k; i ++ ) events.push_back(ets[i]);
}
sort(events.begin(), events.end());
int k = 0, sum = 0;
while (m -- )
{
int hh, mm, ss;
scanf("%d:%d:%d", &hh, &mm, &ss);
int t = hh * 3600 + mm * 60 + ss;
while (k < events.size() && events[k].tm <= t)
{
if (events[k].status == 0) sum ++ ;
else sum -- ;
k ++ ;
}
printf("%d\n", sum);
}
int maxt = 0;
for (auto& item : cars) maxt = max(maxt, get(item.second));
vector<string> res;
for (auto& item : cars)
if (get(item.second) == maxt)
res.push_back(item.first);
sort(res.begin(), res.end());
for (int i = 0; i < res.size(); i ++ ) printf("%s ", res[i].c_str());
printf("%02d:%02d:%02d\n", maxt / 3600, maxt % 3600 / 60, maxt % 60);
return 0;
}
标签:ets,ss,int,res,tm,校园内,++,汽车 来源: https://www.cnblogs.com/xjtfate/p/16615802.html