941. 有效的山脉数组
作者:互联网
给定一个整数数组 A
,如果它是有效的山脉数组就返回 true
,否则返回 false
。
让我们回顾一下,如果 A 满足下述条件,那么它是一个山脉数组:
A.length >= 3
- 在
0 < i < A.length - 1
条件下,存在i
使得:A[0] < A[1] < ... A[i-1] < A[i]
A[i] > A[i+1] > ... > A[B.length - 1]
示例 1:
输入:[2,1] 输出:false
示例 2:
输入:[3,5,5] 输出:false
示例 3:
输入:[0,3,2,1] 输出:true
提示:
0 <= A.length <= 10000
0 <= A[i] <= 10000
class Solution:
def validMountainArray(self, A: 'List[int]') -> 'bool':
if len(A) < 3:
return False
upmountain, downmountain = False, False
# 判断上坡
for i in range(len(A)-1):
if A[i] < A[i + 1]:
upmountain = True
else:
break
# 判断下坡
for j in range(i, len(A) -1):
if A[j] > A[j + 1]:
downmountain = True
else:
downmountain = False
break
# 判断是否为山脉
if j == len(A)-2 and upmountain and downmountain:
return True
else:
return False
def validMountainArray2(self, A: 'List[int]') -> 'bool':
if len(A) < 3:
return False
elif A[0] >= A[1] or A[-1] >= A[-2]:
return False
p = A[0]
flag = True
for x in A[1:]:
# 判断上坡
if flag:
if x > p:
p = x
elif x < p:
flag = False
p = x
else:
return False
# 判断下坡
else:
if x < p:
p = x
else:
return False
return True
#两头双指针应该也可以实现
if __name__=='__main__':
s = Solution()
A = [3,5,3]
print(s.validMountainArray(A))
标签:__,return,len,else,数组,山脉,False,941,True 来源: https://blog.csdn.net/hushaoqiqimingxing/article/details/88650451