void fun1()
{
    std::thread::id tid = std::this_thread::get_id();
    printf("ID is %ld\n", *(long*)&tid);
}

void fun2()
{
    std::thread::id tid = std::this_thread::get_id();
    printf("ID is %ld\n", *(long*)&tid);
}

int main(int argc, char *argv[])
{
    std::thread t1(fun1);
    std::thread t2(fun2);

    std::thread::id t1_tid = t1.get_id();
    //std::thread::id t2_tid = t2.get_id();

    printf("t1 id is %ld\n", *(long*)&t1_tid);
    printf("t2 id is %ld\n", *(long*)& t2.get_id());  // 报错，需要中间变量


    t1.join();
    t2.join();

　　return 0;
}

1. 问题：

编译时出现-fpermissive问题，问题描述是taking address of temporary [-fpermissive]

有一个简单粗暴的解决办法，就是在编译指令里面加入-fpermissive这一条命令，让代码由出错降为警告，从而编译通过，但是不要使用

2. 解决方法：

设置中间变量

标签：std,gcc,thread,++,t2,t1,编译器,tid,id
来源： https://www.cnblogs.com/clovershell/p/16489629.html