os模块——获取上层目录

• import os

  
  # 获取当前目录
  print(os.getcwd())
  print(os.path.abspath(os.path.dirname(__file__)))
  print(os.path.abspath('.'))
  
  # 获取当前文件
  print(os.path.abspath(__file__))
  
  # 获取上级目录
  print(os.path.abspath(os.path.dirname(os.getcwd())))
  print(os.path.abspath(os.path.dirname(os.path.dirname(__file__))))
  print(os.path.abspath(os.path.join(os.getcwd(), "..")))
  
  # 获取上上级目录
  print(os.path.abspath(os.path.join(os.getcwd(), "../..")))
  
  
  os.getcwd()  # Return a unicode string representing the current working directory
  os.path.dirname()  # Returns the directory component of a pathname
  os.path.abspath()  # Return the absolute version of a path
  

标签：__,abspath,模块,print,path,dirname,os,上层
来源： https://www.cnblogs.com/IceSparks/p/16445459.html