函数实现列表中正数更改为负数

>>:

Given a set of numbers, return the additive inverse of each. Each positive becomes negatives, and the negatives become positives.

invert([1,2,3,4,5]) == [-1,-2,-3,-4,-5]
invert([1,-2,3,-4,5]) == [-1,2,-3,4,-5]
invert([]) == []

You can assume that all values are integers. Do not mutate the input array/list.

遍历列表，并将每个项目与给定的数字进行比较，返回时给定的数字应该是负数

>>:想法：

与0 进行大小比较 得到正负信息，负数输出到空列表中，正数 * -1，输出到列表

 1 def invert(lst):
 2     lst_new = []
 3     for n in lst:
 4         if n >= 0:
 5             lst_new.append(n * -1)
 6         else:
 7             lst_new.append(n)
 8     print(lst_new)
 9     
10 invert([1,2,3,4,5])
11 invert([1,-2,3,-4,5])
12 invert([])

[-1, -2, -3, -4, -5]
[-1, -2, -3, -4, -5]
[]

　　

标签：invert,列表,lst,负数,new,正数,append
来源： https://www.cnblogs.com/a001ai-es/p/16406801.html