LeetCode 513 Find Bottom Left Tree Value BFS
作者:互联网
Given the root
of a binary tree, return the leftmost value in the last row of the tree.
Solution
要求出最后一层最左边的节点的值。做法很简单,首先判断是不是最后一层,如果不是,则将该层节点的子节点都 \(push\) 到队列中。
点击查看代码
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
private:
queue<TreeNode *> q;
public:
int findBottomLeftValue(TreeNode* root) {
if(!root->left && !root->right)return root->val;
q.push(root);
while(!q.empty()){
int n = q.size();
bool flag = true;// check if the last layer
TreeNode* tmp;
for(int i=0;i<n;i++){
TreeNode *rt = q.front();q.pop();
if(!rt->right && !rt->left){
if(i==0)tmp = rt;
continue;
}
else{
flag = false;
if(rt->left)q.push(rt->left);
if(rt->right)q.push(rt->right);
}
}
if(flag)return tmp->val;
}
return -1;
}
};
标签:rt,right,TreeNode,val,Bottom,int,Tree,Value,left 来源: https://www.cnblogs.com/xinyu04/p/16332993.html