lc977. 有序数组的平方
作者:互联网
class Solution: def sortedSquares(self, nums: List[int]) -> List[int]: if len(nums) == 0: return [] if len(nums) == 1: return [nums[0] ** 2] result = [] i = 0 square_less_zero = [] while i < len(nums) and nums[i] < 0: square_less_zero.append(nums[i] ** 2) i += 1 j = len(square_less_zero) - 1 while i < len(nums) and j >= 0: if nums[i] ** 2 <= square_less_zero[j]: result.append(nums[i] ** 2) i += 1 else: result.append(square_less_zero[j]) j -= 1 if i < len(nums): while i < len(nums): result.append(nums[i] ** 2) i += 1 if j >= 0: while j >= 0: result.append(square_less_zero[j]) j -= 1 return result
标签:平方,square,return,nums,less,lc977,len,zero,数组 来源: https://www.cnblogs.com/bidesen/p/16208562.html