Floyd
作者:互联网
#include <bits/stdc++.h>
using namespace std;
const int N = 210, INF = 0x3f3f3f3f;
int d[N][N], n, m, q;
void Floyd(){
for (int k = 1; k <= n; k ++ )
for (int i = 1; i <= n; i ++ )
for (int j = 1; j <= n; j ++ )
d[i][j] = min(d[i][j], d[i][k] + d[k][j]);
}
int main(){
cin >> n >> m >> q;
for (int i = 1; i <= n; i ++ )
for (int j = 1; j <= n; j ++ )
if (i == j) d[i][j] = 0;
else d[i][j] = INF;
for (int i = 1; i <= m; i ++ ){
int u, v, w;
cin >> u >> v >> w;
d[u][v] = min(d[u][v], w);
}
Floyd();
while (q--){
int u, v;
cin >> u >> v;
if (d[u][v] >= INF / 2) cout << "impossible\n";
else cout << d[u][v] << "\n";
}
return 0;
}
acwing 模板:https://www.acwing.com/problem/content/856/
标签:www,cout,int,Floyd,INF,acwing 来源: https://www.cnblogs.com/Hamine/p/16163526.html