【C语言】PAT 1002 读入一个正整数 n，计算其各位数字之和，用汉语拼音写出和的每一位数字

#include <stdio.h>
int main()
{
    char ch;
    int sum=0;
    ch = getchar();
    while (ch != '\n')
    {
        sum+=ch-'0';
        ch = getchar();
    }
    int i,s[9];
    for(i=0;sum;)
    {
        s[i++]=sum%10;
        sum=sum/10;
    }
    i--;
    while(i>=0)
    {
        switch(s[i--])
        {
            case 0:printf("ling");break;
            case 1:printf("yi");break;
            case 2:printf("er");break;
            case 3:printf("san");break;
            case 4:printf("si");break;
            case 5:printf("wu");break;
            case 6:printf("liu");break;
            case 7:printf("qi");break;
            case 8:printf("ba");break;
            case 9:printf("jiu");
        }
        if(i>=0)
            printf(" ");
    }
    return 0;
}

标签：case,ch,数字,int,sum,C语言,break,读入,printf
来源： https://blog.csdn.net/yi_zhi_xiao_qi_e/article/details/123252412