day22
作者:互联网
Day 22
Background
今天是学习java的第22天,今天学习的是树的存储。
Description
对于树的储存,用到了循环队列。具体操作是建立了两个队列,一个存值,另一个存对应的在二叉树中的序号。
Code
Code1:对之前写的循环队列进行一个改写,使其适合树的储存。
package datastructure;
public class CircleObjectQueue {
/**
* The tatal space. One space can't used.
*/
public static final int TOTAL_SPACE = 10;
Object[] data;
/**
* 队列的头和尾。
*/
int head;
int tail;
public CircleObjectQueue() {
data = new Object[TOTAL_SPACE];
head = 0;
tail = 0;
} // Of the first constructure
public void enQueue(Object paraValue) {
if ((tail + 1) % TOTAL_SPACE == head) {
System.out.println("Queue full.");
return;
} // Of if
data[tail % TOTAL_SPACE] = paraValue;
tail++;
} // Of enQueue
public Object deQueue() {
if (tail == head) {
return null;
}
Object resultValue = data[head % TOTAL_SPACE];
head++;
return resultValue;
} // Of deQueue
public String toString() {
String resultString = "";
if (head == tail) {
return "empty";
} // Of if
for (int i = head; i < tail - 1; i++) {
resultString += data[i % TOTAL_SPACE] + ", ";
} // Of for i
resultString += data[(tail - 1) % TOTAL_SPACE];
return resultString;
} // Of toString
public static void main(String[] args) {
CircleObjectQueue tempQueue = new CircleObjectQueue();
} // Of main
}
Code 2 存储二叉树
package datastructure;
import java.util.Arrays;
import datastructure.CircleObjectQueue.*;
public class BinaryCharTree {
/**
* The value of node.
*/
char value;
/**
* 二叉树的左孩子。
*/
BinaryCharTree leftChild;
/**
* 二叉树的右孩子。
*/
BinaryCharTree rightChild;
/**
**************
* The first constructor.
*
* @param paraValue The given value.
**************
*/
public BinaryCharTree(char paraValue) {
value = paraValue;
leftChild = null;
rightChild = null;
} // Of the first construe
public static BinaryCharTree manualConstructTree() {
// step 1. Creat root.
BinaryCharTree resultTree = new BinaryCharTree('a');
// step 2. creat children and linked them.
BinaryCharTree tempTreeB = new BinaryCharTree('b');
BinaryCharTree tempTreeC = new BinaryCharTree('c');
BinaryCharTree tempTreeD = new BinaryCharTree('d');
BinaryCharTree tempTreeE = new BinaryCharTree('e');
BinaryCharTree tempTreeF = new BinaryCharTree('f');
BinaryCharTree tempTreeG = new BinaryCharTree('g');
// Link strat
resultTree.leftChild = tempTreeB;
resultTree.rightChild = tempTreeC;
tempTreeB.rightChild = tempTreeD;
tempTreeC.leftChild = tempTreeE;
tempTreeD.leftChild = tempTreeF;
tempTreeD.rightChild = tempTreeG;
return resultTree;
} // Of manualConstructTree
/**
**************
* 先根、中根、后根遍历树。
**************
*/
public void preOrderVisit() {
System.out.print(value + " ");
if (leftChild != null) {
leftChild.preOrderVisit();
} // Of if
if (rightChild != null) {
rightChild.preOrderVisit();
} // Of if
} // Of preOrderVisit
public void inOrderVisit() {
if (leftChild != null) {
leftChild.inOrderVisit();
} // Of if
System.out.print(value + " ");
if (rightChild != null) {
rightChild.inOrderVisit();
} // Of if
}
public void postOrderVisit() {
if (leftChild != null) {
leftChild.postOrderVisit();
} // Of if
if (rightChild != null) {
rightChild.postOrderVisit();
} // Of if
System.out.print(value + " ");
}
public int getDepth() {
if ((leftChild == null) && (rightChild == null)) {
return 1;
} // Of if
// check left
int tempLeftDepth = 0;
if (leftChild != null) {
tempLeftDepth = leftChild.getDepth();
} // Of if
// Check right
int tempRightDepth = 0;
if (rightChild != null) {
tempRightDepth = rightChild.getDepth();
} // Of if
if (tempLeftDepth >= tempRightDepth) {
return tempLeftDepth + 1;
} else {
return tempRightDepth + 1;
} // Of if
} // Of getDepth
// 遍历时存储节点中的值。
char[] valueArray;
// 二叉树的索引。
int[] indicesArray;
public void toDataArrays() {
int tempLength = getNumNodes();
valueArray = new char[tempLength];
indicesArray = new int[tempLength];
int i = 0;
// Traverse and convert at the same time.
CircleObjectQueue tempQueue = new CircleObjectQueue();
tempQueue.enQueue(this);
CircleObjectQueue tempIntQueue = new CircleObjectQueue();
tempIntQueue.enQueue(0);
BinaryCharTree tempTree = (BinaryCharTree) tempQueue.deQueue();
int tempIndex = (int) tempIntQueue.deQueue();
while (tempTree != null) {
valueArray[i] = tempTree.value;
indicesArray[i] = tempIndex;
i++;
if (tempTree.leftChild != null) {
tempQueue.enQueue(tempTree.leftChild);
tempIntQueue.enQueue(tempIndex * 2 + 1);
} // Of if
if (tempTree.rightChild != null) {
tempQueue.enQueue(tempTree.rightChild);
tempIntQueue.enQueue(tempIndex * 2 + 2);
} // Of if
tempTree = (BinaryCharTree) tempQueue.deQueue();
if (tempTree != null)
tempIndex = (int) tempIntQueue.deQueue();
} // Of while
}
public int getNumNodes() {
if ((leftChild == null) && (rightChild == null)) {
return 1;
} // Of if
int tempLeftNodes = 0;
if (leftChild != null) {
tempLeftNodes = leftChild.getNumNodes();
} // Of if
int tempRightNodes = 0;
if (rightChild != null) {
tempRightNodes = rightChild.getNumNodes();
} // Of if
return tempLeftNodes + tempRightNodes + 1;
}// Of getNumNodes
/**
*********************
* The entrance of the program.
*
* @param args Not used now.
*********************
*/
public static void main(String args[]) {
BinaryCharTree tempTree = manualConstructTree();
System.out.println("\r\nPreorder visit:");
tempTree.preOrderVisit();
System.out.println("\r\nIn-order visit:");
tempTree.inOrderVisit();
System.out.println("\r\nPost-order visit:");
tempTree.postOrderVisit();
System.out.println("\r\n\r\nThe depth is: " + tempTree.getDepth());
System.out.println("The number of nodes is: " + tempTree.getNumNodes());
tempTree.toDataArrays();
System.out.println("The values are: " + Arrays.toString(tempTree.valueArray));
System.out.println("The indices are: " + Arrays.toString(tempTree.indicesArray));
}// Of main
}
运行结果:
标签:BinaryCharTree,rightChild,day22,leftChild,tempTree,null,public 来源: https://blog.csdn.net/qq_43571222/article/details/123193517