1018 Public Bike Management (30 分)
作者:互联网
坑:路径后面车站多出来的车不能弥补前面的空缺
#include <bits/stdc++.h>
#define LOCAL
using namespace std;
template<typename A, typename B> ostream& operator<<(ostream &os, const pair<A, B> &p) { return os << '(' << p.first << ", " << p.second << ')'; }
template<typename T_container, typename T = typename enable_if<!is_same<T_container, string>::value, typename T_container::value_type>::type> ostream& operator<<(ostream &os, const T_container &v) { os << '{'; string sep; for (const T &x : v) os << sep << x, sep = ", "; return os << '}'; }
void dbg_out() { cerr << endl; }
template<typename Head, typename... Tail> void dbg_out(Head H, Tail... T) { cerr << ' ' << H; dbg_out(T...); }
#ifdef LOCAL
#define dbg(...) cerr << "(" << #__VA_ARGS__ << "):", dbg_out(__VA_ARGS__)
#else
#define dbg(...)
#endif
#define vec vector
#define ll long long
#define ld long double
#define sza(x) ((int)x.size())
#define all(a) (a).begin(), (a).end()
const int MAX_N = 1e5 + 5;
const ll MOD = 1e9 + 7;
const ll INF = 1e9;
const ld EPS = 1e-9;
int Cmax, N, Sp, M;
int C[510];
map<int, map<int, int>> ma;
int Min;
int st[510];
vec<int> path;
int send = INF, rec = INF;
int vis[510];
int dist[510];
void dijkstra(int start){
memset(dist, 0x3f, sizeof dist);
dist[start] = 0;
for(int i = 0; i <= N; i ++){
int k = -1;
for(int j = 0; j <= N; j ++)
if(vis[j] == 0 && (k == -1 || dist[k] > dist[j]))
k = j;
vis[k] = 1;
for(auto t : ma[k]){
dist[t.first] = min(dist[t.first], dist[k] + t.second); // 为什么这里不需要特判vis = 0
}
}
}
void dfs(int u, int w, int sd, int rc, vec<int> &p){
st[u] = 1;
if(w > Min) return;
if(u == Sp){
if(Min == w){
if(sd < send){
send = sd;
rec = rc;
path = p;
}else if(sd == send && rc < rec){
rec = rc;
path = p;
}
}
return;
}
for(auto t : ma[u]){
if(st[t.first] == 0){
p.push_back(t.first);
int val = C[t.first] - Cmax / 2;
if(val < 0){
int ssd = sd - val - min(-val, rc);
int rrc = rc - min(-val, rc);
dfs(t.first, w + t.second, ssd, rrc, p);
}else{
int rrc = rc + val;
dfs(t.first, w + t.second, sd, rrc, p);
}
st[t.first] = 0;
p.pop_back();
}
}
}
void solve() {
cin >> Cmax >> N >> Sp >> M;
for(int i = 1; i <= N; i ++){
cin >> C[i];
}
for(int i = 0; i < M; i ++){
int a, b, w;
cin >> a >> b >> w;
if(ma[a].count(b) == 0){
ma[a][b] = ma[b][a] = w;
}else{
ma[a][b] = min(ma[a][b], w);
ma[b][a] = min(ma[b][a], w);
}
}
dijkstra(0);
Min = dist[Sp];
// cout << Min << endl;
st[0] = 1;
vec<int> p{0};
for(auto t : ma[0]){
p.push_back(t.first);
int sd = max(Cmax / 2 - C[t.first], 0);
int rc = max(C[t.first] - Cmax / 2, 0);
dfs(t.first, t.second, sd, rc, p);
p.pop_back();
}
cout << send << ' ';
cout << path[0];
for(int i = 1; i < path.size(); i ++) cout << "->" << path[i];
cout << ' ' << rec << endl;
}
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
int tc = 1;
// cin >> tc;
for (int t = 1; t <= tc; t++) {
// cout << "Case #" << t << ": ";
solve();
}
}
标签:Management,ma,int,Bike,1018,rc,dist,sd,first 来源: https://www.cnblogs.com/tomori/p/15863914.html