1083 List Grades

Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade’s interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student’s name and ID, separated by one space. If there is no student’s grade in that interval, output NONE instead.

Sample Input 1:

4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100

Sample Output 1:

Mike CS991301
Mary EE990830
Joe Math990112

#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;

struct student
{
  char name[15];
  char id[15];
  int grade;
}stu[50];

bool cmp(student s1, student s2)
{
  return s1.grade > s2.grade;
}

int main()
{
  int n;
  scanf_s("%d", &n);
  for (int i = 0; i < n; i++)
  {
    scanf_s("%s %s %d", &stu[i].name, sizeof(char) * 15, &stu[i].id, sizeof(char) * 15, &stu[i].grade);
  }
  sort(stu, stu + n, cmp);

  int min, max;
  int num = 0;
  scanf_s("%d%d", &min, &max);
  for (int i = 0; i < n; i++)
  {
    if (stu[i].grade >= min && stu[i].grade <= max)
    {
      printf("%s %s\n", stu[i].name, stu[i].id);
      num++;
    }
  }
  if (num == 0)
  {
    printf("NONE\n");
  }

}

标签：int,1083,name,grade,List,stu,Grades,student,ID
来源： https://blog.csdn.net/weixin_44230791/article/details/122786714