PAT (Basic Level) Practice 1057 数零壹 (20 分)
作者:互联网
题目:1057 数零壹 (20 分)
来源:PAT (Basic Level) Practice
传送门 1057 数零壹
题面
题意:统计字符串中字母序号之和并转化为二进制,输出该二进制数的0和1的个数
思路:见代码
Code
点击查看代码
#include<iostream>
#include<string>
using namespace std;
typedef long long ll;
ll n[3];
int main() {
string s;
ll ans = 0;
getline(cin, s);
for (int i = 0; i < s.size(); i++) {
s[i] = tolower(s[i]);
if (s[i] <= 'z' && s[i] >= 'a') {
ans += s[i] - 'a' + 1;
}
}
while (ans) {
n[ans % 2]++;
ans /= 2;
}
cout << n[0] << " " << n[1];
return 0;
}
标签:Basic,PAT,Level,ll,1057,ans,零壹 来源: https://www.cnblogs.com/w0x59-h/p/15860199.html