P2694 接金币（贪心策略）

P2694 接金币 - 洛谷 | 计算机科学教育新生态 (luogu.com.cn)

#include<bits/stdc++.h>

using namespace std;

struct node
{
	int x,y;
}a[60];

bool cmp(node a,node b)
{
	return a.y < b.y;//y坐标小的在前面 
}
int main()
{
	int g,n;
	scanf("%d",&g);
	while(g--)
	{
		memset(a,0,sizeof(a));//数组初始化
		scanf("%d",&n);
		for(int i = 1; i <= n; i++)
		 	scanf("%d%d",&a[i].x,&a[i].y);
		sort(a + 1, a + 1 + n, cmp);
		int flag = 0; 	
		for(int i = 1; i <= n; i++)
		{
			if(abs(a[i].x - a[i-1].x) > a[i].y - a[i-1].y)
			{
				flag = 1;
				cout << "Notabletocatch" << endl;
				break;
			}
		}
		if(flag == 0) cout << "Abletocatch" << endl;
	}
	
	
	return  0;
}

标签：node,cn,int,P2694,金币,scanf,贪心
来源： https://blog.csdn.net/EDGNB6666/article/details/122750227