相交链表的相交节点

给你两个单链表的头节点headA和headB，请你找出并返回两个单链表相交的起始节点。如果两个链表不存在相交节点，返回null。

输入：intersectVal = 8, listA = [4,1,8,4,5], listB = [5,6,1,8,4,5], skipA = 2, skipB = 3
输出：Intersected at '8' 

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) {
 *         val = x;
 *         next = null;
 *     }
 * }
 */
public class Solution {
    public ListNode getIntersectionNode(ListNode headA, ListNode headB) {
        if (headA == null || headB == null) {
            return null;
        }
        ListNode pA = headA, pB = headB;
        while (pA != pB) {
            if(pA == null){
                pA = headB;
            }else{
                pA = pA.next;
            }
            if(pB == null){
                pB = headA;
            }else{
                pB = pB.next;
            }
        }
        return pA;
    }
}

标签：pB,ListNode,相交,链表,pA,headB,headA,null,节点
来源： https://blog.csdn.net/voilde/article/details/122377256