位运算判断是否是2的幂

4->100
3->011
100 & 011 -> 0

#include<iostream>
using namespace std;
int main()
{
	int n; //n>0
	cin>>n;
	if( n & (n-1) )
		cout<<"no\n";
	else
		cout<<"yes\n";
	return 0;
}

标签：std,判断,运算,int,namespace,是否是,011,100,main
来源： https://blog.csdn.net/weixin_52341477/article/details/122289064