175. 组合两个表
作者:互联网
表1: Person
+-------------+---------+
| 列名 | 类型 |
+-------------+---------+
| PersonId | int |
| FirstName | varchar |
| LastName | varchar |
+-------------+---------+
PersonId 是上表主键
表2: Address
+-------------+---------+
| 列名 | 类型 |
+-------------+---------+
| AddressId | int |
| PersonId | int |
| City | varchar |
| State | varchar |
+-------------+---------+
AddressId 是上表主键
编写一个 SQL 查询,满足条件:无论 person 是否有地址信息,都需要基于上述两表提供 person 的以下信息:
FirstName, LastName, City, State
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/combine-two-tables
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# Write your MySQL query statement below
SELECT p.FirstName, p.LastName, a.City, a.State FROM Person p LEFT JOIN Address a
on p.PersonId = a.PersonId
标签:City,FirstName,varchar,组合,+-------------+---------+,PersonId,int,两个,175 来源: https://www.cnblogs.com/tianyiya/p/15700363.html