poj 3095（水题）

#include<iostream>
#include<cmath> 
#include<cstring>
using namespace std;
int main(){
    char a[80],d[]={'/','\\','.','|','_'};
    int len;
    double sum;
    while(scanf("%s",a)==1&&strcmp(a,"#")){
        len = strlen(a);
        sum = 0;
        for(int i=0;i<len;i++){
            if(a[i]=='_'){
                sum += 1;
            }
            if(a[i]=='|'){
                for(int j=i-1;j>-1;j--){
                    if(a[j]=='.')break;
                    else if(a[j]=='|'||a[j]=='\\'){
                        sum += 0.5;
                        break;
                    }
                }
                for(int j=i+1;j<len;j++){
                    if(a[j]=='.')break;
                    else if(a[j]=='|'||a[j]=='/'){
                        sum += 0.5;
                        break;
                    }
                }
            }
            if(a[i]=='/'){
                for(int j=i-1;j>-1;j--){
                    if(a[j]=='.')break;
                    else if(a[j]=='|'||a[j]=='\\'){
                        sum += 1;
                        break;
                    }
                }
            }
            if(a[i]=='\\'){
                for(int j=i+1;j<len;j++){
                    if(a[j]=='.')break;
                    else if(a[j]=='|'||a[j]=='/'){
                        sum += 1; 
                        break;
                    }
                }
            }
        }
        printf("%.0lf\n",floor(100-100.0*sum/len));
    }
    return 0;
}

标签：水题,int,sum,len,else,break,poj,3095,include
来源： https://www.cnblogs.com/stevenzrx/p/15647055.html