poj 3253（水题）

#include<iostream>
#include<algorithm>
using namespace std;
int cmp(long long p,long long q){
    if(p>q)return true;
    return false;
}
int main(){
    int n,i,j;
    long long data[20005],result,tmp;
    scanf("%d",&n);
    for(int i=0;i<n;i++){
        scanf("%d",&data[i]);
    }
    result = 0; 
    sort(data,data+n,cmp);
    for(i=0;i<n-1;i++){
        data[n-2-i] = data[n-2-i]+data[n-1-i];
        result += data[n-2-i];
        tmp = data[n-2-i];
        for(j=n-2-i;j>=1;j--){
            if(data[j-1]<tmp){
                data[j] = data[j-1];
            }
            else{
                break;
            }
        }
        data[j] = tmp;
    }
    if(n==1)
        printf("%lld\n",data[0]);
    else
        printf("%lld\n",result);
    return 0;
}

标签：std,return,水题,int,3253,long,poj,include,data
来源： https://www.cnblogs.com/stevenzrx/p/15640067.html