剑指offer——面试题32：从上到下打印二叉树

void BFS(BinaryTreeNode* pRoot)
{
    if(pRoot==nullptr)
    {
        cout<<"empty binary tree!"<<endl;
        return;
    }
    queue<BinaryTreeNode*>pNode;
    pNode.push(pRoot);
    while(!pNode.empty())
    {
        BinaryTreeNode* pFront=pNode.front();
        pNode.pop();
        cout<<pFront->m_Value<<' ';
        if(pFront->m_pLeft!=nullptr)
            pNode.push(pFront->m_pLeft);
        if(pFront->m_pRight!=nullptr)
            pNode.push(pFront->m_pRight);
    }
    cout<<endl;
}

 1 #include"BinaryTree.h"
 2 
 3 void Test()
 4 {
 5     BFS(nullptr);
 6     BinaryTreeNode* pNode1=CreateBinaryTreeNode(8);
 7     BFS(pNode1);
 8     BinaryTreeNode* pNode2=CreateBinaryTreeNode(6);
 9     ConnectTreeNodes(pNode1,pNode2,nullptr);
10     BFS(pNode1);
11     ConnectTreeNodes(pNode1,nullptr,pNode2);
12     BFS(pNode1);
13     BinaryTreeNode* pNode3=CreateBinaryTreeNode(10);
14     ConnectTreeNodes(pNode1,pNode2,pNode3);
15     BFS(pNode1);
16 }
17 
18 int main()
19 {
20     Test();
21     return 0;
22 }

标签：面试题,offer,pNode2,pNode1,nullptr,BFS,pNode,二叉树,BinaryTreeNode
来源： https://www.cnblogs.com/acm-jing/p/10430269.html