剑指offer-用两个栈实现队列05
作者:互联网
class Solution: def __init__(self): self.stackpush=[] self.stackpop=[] def push(self, node): # write code here self.stackpush.append(node) def pop(self): # return xx if len(self.stackpop)==0: while len(self.stackpush) is not 0: self.stackpop.append(self.stackpush.pop(-1)) else: return self.stackpop.pop(-1) return self.stackpop.pop(-1)
思路:设置两个栈。stackpush用于入队列,stackpop用于出队列,当栈stackpop不为空时,直接出队列。当stackpop为空时,把stackpush出栈,stackpop入栈。直到stackpush为空,之后再出队列栈,完成出队列
标签:return,offer,队列,self,05,stackpop,pop,stackpush 来源: https://www.cnblogs.com/zhaiyansheng/p/10411349.html