首页 > 其他分享> > 基于scott做练习1

基于scott做练习1

2021-10-21 22:34:48 作者：互联网

根据ER图创建表结构

/*
Navicat Oracle Data Transfer
Oracle Client Version : 10.2.0.5.0

Source Server         : MyOracle
Source Server Version : 110200
Source Host           : localhost:1521
Source Schema         : KAIFAMIAO

Target Server Type    : ORACLE
Target Server Version : 110200
File Encoding         : 65001

Date: 2021-10-19 17:16:36
*/


-- ----------------------------
-- Table structure for DEPT
-- ----------------------------
DROP TABLE "KAIFAMIAO"."DEPT";
CREATE TABLE "KAIFAMIAO"."DEPT" (
"ID" NUMBER NOT NULL ,
"DNAME" VARCHAR2(20 BYTE) NULL ,
"LOC" VARCHAR2(100 BYTE) NULL 
)
LOGGING
NOCOMPRESS
NOCACHE

;

-- ----------------------------
-- Records of DEPT
-- ----------------------------
INSERT INTO "KAIFAMIAO"."DEPT" VALUES ('1001', '开发部', '西安');
INSERT INTO "KAIFAMIAO"."DEPT" VALUES ('1002', '市场部', '兰州');
INSERT INTO "KAIFAMIAO"."DEPT" VALUES ('1003', '销售部', '北京');

-- ----------------------------
-- Table structure for EMP
-- ----------------------------
DROP TABLE "KAIFAMIAO"."EMP";
CREATE TABLE "KAIFAMIAO"."EMP" (
"ID" NUMBER NOT NULL ,
"ENAME" VARCHAR2(50 BYTE) NULL ,
"JOB_ID" NUMBER NULL ,
"MGR" NUMBER NULL ,
"JOINDATE" DATE NULL ,
"SALARY" NUMBER(7,2) NULL ,
"BONUS" NUMBER(7,2) NULL ,
"DEPT_ID" NUMBER NULL 
)
LOGGING
NOCOMPRESS
NOCACHE

;

-- ----------------------------
-- Records of EMP
-- ----------------------------
INSERT INTO "KAIFAMIAO"."EMP" VALUES ('10001', '张斌', '102', '0', TO_DATE('2019-08-09 06:30:10', 'YYYY-MM-DD HH24:MI:SS'), '9500', '8000', null);
INSERT INTO "KAIFAMIAO"."EMP" VALUES ('10002', '顾辞', '101', '1', TO_DATE('2019-08-09 06:30:10', 'YYYY-MM-DD HH24:MI:SS'), '8500', '5000', '1001');
INSERT INTO "KAIFAMIAO"."EMP" VALUES ('10003', '陈平安', '103', '2', TO_DATE('2019-10-09 06:30:10', 'YYYY-MM-DD HH24:MI:SS'), '8500', '5000', '1001');
INSERT INTO "KAIFAMIAO"."EMP" VALUES ('10004', '赔钱', '104', '2', TO_DATE('2019-10-10 06:30:10', 'YYYY-MM-DD HH24:MI:SS'), '8300', '5000', '1001');
INSERT INTO "KAIFAMIAO"."EMP" VALUES ('10005', '张三丰', '101', '1', TO_DATE('2019-09-19 06:30:10', 'YYYY-MM-DD HH24:MI:SS'), '8500', '4000', '1002');
INSERT INTO "KAIFAMIAO"."EMP" VALUES ('10006', '曹慈', '101', '1', TO_DATE('2019-10-18 18:30:10', 'YYYY-MM-DD HH24:MI:SS'), '8500', '3900', '1003');
INSERT INTO "KAIFAMIAO"."EMP" VALUES ('10007', '左右', '106', '2', TO_DATE('2019-10-13 15:30:10', 'YYYY-MM-DD HH24:MI:SS'), '4500', '2500', '1003');
INSERT INTO "KAIFAMIAO"."EMP" VALUES ('10008', '白也', '105', '2', TO_DATE('2019-10-01 10:40:10', 'YYYY-MM-DD HH24:MI:SS'), '4500', '2000', '1002');
INSERT INTO "KAIFAMIAO"."EMP" VALUES ('10009', '助理1', '107', '3', TO_DATE('2020-04-29 10:40:10', 'YYYY-MM-DD HH24:MI:SS'), '4000', '0', '1001');
INSERT INTO "KAIFAMIAO"."EMP" VALUES ('100010', '助理2', '107', '3', TO_DATE('2021-05-10 10:40:10', 'YYYY-MM-DD HH24:MI:SS'), '4000', '1000', '1001');
INSERT INTO "KAIFAMIAO"."EMP" VALUES ('100011', '助理3', '107', '3', TO_DATE('2019-04-20 10:40:10', 'YYYY-MM-DD HH24:MI:SS'), '3000', '0', '1002');
INSERT INTO "KAIFAMIAO"."EMP" VALUES ('100012', '助理4', '107', '3', TO_DATE('2018-10-29 10:40:10', 'YYYY-MM-DD HH24:MI:SS'), '3000', '1000', '1003');

-- ----------------------------
-- Table structure for INFOS
-- ----------------------------
DROP TABLE "KAIFAMIAO"."INFOS";
CREATE TABLE "KAIFAMIAO"."INFOS" (
"STUID" VARCHAR2(7 BYTE) NOT NULL ,
"STUNAME" VARCHAR2(10 BYTE) NOT NULL ,
"GENDER" VARCHAR2(5 BYTE) NOT NULL ,
"AGE" NUMBER(2) NOT NULL ,
"SEAT" NUMBER(2) NOT NULL ,
"ENROLLDATE" DATE NULL ,
"STUADDRESS" VARCHAR2(50 CHAR) DEFAULT '地址不详'  NOT NULL ,
"CLASSNO" VARCHAR2(4 BYTE) NOT NULL 
)
LOGGING
NOCOMPRESS
NOCACHE

;

-- ----------------------------
-- Records of INFOS
-- ----------------------------
INSERT INTO "KAIFAMIAO"."INFOS" VALUES ('s100102', '林冲', '男', '22', '2', TO_DATE('2021-10-19 14:45:14', 'YYYY-MM-DD HH24:MI:SS'), '西安', '1001');
INSERT INTO "KAIFAMIAO"."INFOS" VALUES ('s100104', '阮小二', '男', '26', '3', TO_DATE('2021-10-18 21:16:10', 'YYYY-MM-DD HH24:MI:SS'), '地址不详', '1001');

-- ----------------------------
-- Table structure for JOB
-- ----------------------------
DROP TABLE "KAIFAMIAO"."JOB";
CREATE TABLE "KAIFAMIAO"."JOB" (
"ID" NUMBER NOT NULL ,
"JNAME" VARCHAR2(30 BYTE) NULL ,
"DESCRIPTION" VARCHAR2(200 BYTE) NULL 
)
LOGGING
NOCOMPRESS
NOCACHE

;

-- ----------------------------
-- Records of JOB
-- ----------------------------
INSERT INTO "KAIFAMIAO"."JOB" VALUES ('101', '部门经理', '负责整个部门的具体工作，向总经理汇报');
INSERT INTO "KAIFAMIAO"."JOB" VALUES ('103', '开发工程师', '负责部门的具体开发工作，向部门经理汇报');
INSERT INTO "KAIFAMIAO"."JOB" VALUES ('102', '总经理', '负责公司整体的运行');
INSERT INTO "KAIFAMIAO"."JOB" VALUES ('104', '运维测试工程师', '负责开发部产品的运维测试工作');
INSERT INTO "KAIFAMIAO"."JOB" VALUES ('105', '市场开发人员', '负责公司市场的开发拓展');
INSERT INTO "KAIFAMIAO"."JOB" VALUES ('106', '销售员', '负责销售公司产品');
INSERT INTO "KAIFAMIAO"."JOB" VALUES ('107', '助理', '协助上一级员工完成工作');

-- ----------------------------
-- Table structure for SALARYGRADE
-- ----------------------------
DROP TABLE "KAIFAMIAO"."SALARYGRADE";
CREATE TABLE "KAIFAMIAO"."SALARYGRADE" (
"GRADE" NUMBER NOT NULL ,
"LOSALARY" NUMBER NULL ,
"HISALARY" NUMBER NULL 
)
LOGGING
NOCOMPRESS
NOCACHE

;

-- ----------------------------
-- Records of SALARYGRADE
-- ----------------------------
INSERT INTO "KAIFAMIAO"."SALARYGRADE" VALUES ('1', '9000', '10000');
INSERT INTO "KAIFAMIAO"."SALARYGRADE" VALUES ('2', '8000', '9000');
INSERT INTO "KAIFAMIAO"."SALARYGRADE" VALUES ('3', '5500', '7000');
INSERT INTO "KAIFAMIAO"."SALARYGRADE" VALUES ('4', '3000', '5000');

-- ----------------------------
-- Table structure for SCORES
-- ----------------------------
DROP TABLE "KAIFAMIAO"."SCORES";
CREATE TABLE "KAIFAMIAO"."SCORES" (
"ID" NUMBER NULL ,
"TERM" VARCHAR2(2 BYTE) NULL ,
"STUID" VARCHAR2(7 BYTE) NOT NULL ,
"EXAMNO" VARCHAR2(7 BYTE) NOT NULL ,
"WRITTENSCORE" NUMBER(4,1) NOT NULL ,
"LABSCORE" NUMBER(4,1) NOT NULL 
)
LOGGING
NOCOMPRESS
NOCACHE

;

-- ----------------------------
-- Records of SCORES
-- ----------------------------
INSERT INTO "KAIFAMIAO"."SCORES" VALUES ('1001', 'S2', 's100104', '4', '98', '89');

-- ----------------------------
-- Sequence structure for MYSEQ
-- ----------------------------
DROP SEQUENCE "KAIFAMIAO"."MYSEQ";
CREATE SEQUENCE "KAIFAMIAO"."MYSEQ"
 INCREMENT BY 1
 MINVALUE 1
 MAXVALUE 9999999999999999999999999999
 START WITH 21
 CACHE 20;

-- ----------------------------
-- Indexes structure for table DEPT
-- ----------------------------

-- ----------------------------
-- Primary Key structure for table DEPT
-- ----------------------------
ALTER TABLE "KAIFAMIAO"."DEPT" ADD PRIMARY KEY ("ID");

-- ----------------------------
-- Indexes structure for table EMP
-- ----------------------------

-- ----------------------------
-- Primary Key structure for table EMP
-- ----------------------------
ALTER TABLE "KAIFAMIAO"."EMP" ADD PRIMARY KEY ("ID");

-- ----------------------------
-- Uniques structure for table INFOS
-- ----------------------------
ALTER TABLE "KAIFAMIAO"."INFOS" ADD UNIQUE ("STUNAME");
ALTER TABLE "KAIFAMIAO"."INFOS" ADD UNIQUE ("STUID");

-- ----------------------------
-- Checks structure for table INFOS
-- ----------------------------
ALTER TABLE "KAIFAMIAO"."INFOS" ADD CHECK (AGE >=0 AND AGE<=100);
ALTER TABLE "KAIFAMIAO"."INFOS" ADD CHECK ((CLASSNO >='1001' AND CLASSNO<='1999') OR 
(CLASSNO >='2001' AND CLASSNO<='2999'));
ALTER TABLE "KAIFAMIAO"."INFOS" ADD CHECK (GENDER = '男' OR GENDER = '女');
ALTER TABLE "KAIFAMIAO"."INFOS" ADD CHECK (SEAT >=0 AND SEAT <=50);
ALTER TABLE "KAIFAMIAO"."INFOS" ADD CHECK ("STUID" IS NOT NULL);
ALTER TABLE "KAIFAMIAO"."INFOS" ADD CHECK ("STUNAME" IS NOT NULL);
ALTER TABLE "KAIFAMIAO"."INFOS" ADD CHECK ("GENDER" IS NOT NULL);
ALTER TABLE "KAIFAMIAO"."INFOS" ADD CHECK ("AGE" IS NOT NULL);
ALTER TABLE "KAIFAMIAO"."INFOS" ADD CHECK ("SEAT" IS NOT NULL);
ALTER TABLE "KAIFAMIAO"."INFOS" ADD CHECK ("STUADDRESS" IS NOT NULL);
ALTER TABLE "KAIFAMIAO"."INFOS" ADD CHECK ("CLASSNO" IS NOT NULL);

-- ----------------------------
-- Indexes structure for table JOB
-- ----------------------------

-- ----------------------------
-- Primary Key structure for table JOB
-- ----------------------------
ALTER TABLE "KAIFAMIAO"."JOB" ADD PRIMARY KEY ("ID");

-- ----------------------------
-- Indexes structure for table SALARYGRADE
-- ----------------------------

-- ----------------------------
-- Primary Key structure for table SALARYGRADE
-- ----------------------------
ALTER TABLE "KAIFAMIAO"."SALARYGRADE" ADD PRIMARY KEY ("GRADE");

-- ----------------------------
-- Checks structure for table SCORES
-- ----------------------------
ALTER TABLE "KAIFAMIAO"."SCORES" ADD CHECK (TERM = 'S1' OR TERM ='S2');
ALTER TABLE "KAIFAMIAO"."SCORES" ADD CHECK ("STUID" IS NOT NULL);
ALTER TABLE "KAIFAMIAO"."SCORES" ADD CHECK ("EXAMNO" IS NOT NULL);
ALTER TABLE "KAIFAMIAO"."SCORES" ADD CHECK ("WRITTENSCORE" IS NOT NULL);
ALTER TABLE "KAIFAMIAO"."SCORES" ADD CHECK ("LABSCORE" IS NOT NULL);

-- ----------------------------
-- Foreign Key structure for table "KAIFAMIAO"."EMP"
-- ----------------------------
ALTER TABLE "KAIFAMIAO"."EMP" ADD FOREIGN KEY ("DEPT_ID") REFERENCES "KAIFAMIAO"."DEPT" ("ID");
ALTER TABLE "KAIFAMIAO"."EMP" ADD FOREIGN KEY ("JOB_ID") REFERENCES "KAIFAMIAO"."JOB" ("ID");

-- ----------------------------
-- Foreign Key structure for table "KAIFAMIAO"."SCORES"
-- ----------------------------
ALTER TABLE "KAIFAMIAO"."SCORES" ADD FOREIGN KEY ("STUID") REFERENCES "KAIFAMIAO"."INFOS" ("STUID");

使用上表完成数据查询

1.选择某一个部门的所有员工

select e.id, e.ename, j.jname, e.salary, e.bonus, d.dname 
       from job j join emp e on j.id = e.job_id 
            join dept d on d.id = e.dept_id 
                 where e.dept_id = 1003;

2.列出所有第二级员工的姓名，编号，部门编号

select e.ename, e.id, e.dept_id from emp e where mgr = 2;

3.找出奖金高于薪水的员工

select * from emp where bonus > salary;

4.找出奖金高于薪水60%的员工

select * from emp where bonus > salary * 0.6;

5.找出部门某个部门的经理和某个部门的所有第二级员工的详细资料【两个部门不相同】

select * from emp where dept_id = 1001 and mgr = 1 or mgr = (select mgr from emp where dept_id = 1002 and mgr = 2);

6.找出部门某个部门的经理，某个部门的所有第二级员工，既不是经理又不是办事员但其薪资小于或等于3000的员工的详细工作

SQL> select ename, j.jname, salary 
	from emp join job j on emp.job_id = j.id 
		where (emp.mgr = 1 and emp.dept_id = 1001) 
			or (emp.mgr = 2 and emp.dept_id = 1002) 
				or (emp.mgr != 1 and emp.mgr != 2 and emp.salary > 2000);

7.找出收取奖金的员工的不同工作

-- select distinct j.jname from emp e join job j on e.job_id = j.id where e.bonus != 0;
 select distinct j.jname from emp e join job j on e.job_id = j.id where e.bonus is not null;

8.找出不收取奖金或者奖金低于5000 的员工

select distinct j.jname from emp e join job j on e.job_id = j.id where e.bonus = 0 or e.bonus < 5000;

9.找出各月倒数第三天受雇的所有员工

SELECT * FROM EMP WHERE JOINDATE = LAST_DAY(JOINDATE)-2 ;

10.找出早于2年前受雇的员工

select * from emp where JOINDATE <= add_months(sysdate,-24);
select * from emp where JOINDATE <= JOINDATE + INTERVAL '-2' YEAR;

基于SCOTT 示例数据库进行练习

1.列出至少一个员工的所有部门

-- 在 SQL 中增加 HAVING 子句原因是，WHERE 关键字无法与聚合函数一起使用。HAVING 子句可以让我们筛选分组后的各组数据。
SELECT E.DEPTNO,D.DNAME,COUNT(E.EMPNO) AS EMPNUM FROM EMP E 
       JOIN DEPT D ON E.DEPTNO = D.DEPTNO 
       GROUP BY E.DEPTNO,D.DNAME
       HAVING COUNT(E.EMPNO) > 1
-- 这样写不太严谨 如果 编号和名字不对应就会有问题 所以上面可以不去查 名字 查编号用编号分组
-- 想要全部列出 可以用分词查询结果作为表和dept表连接
-- having 写 group by 之后之前都可以
select d.deptno, d.dname, d1.cou from dept d,
		(select deptno, count(empno) cou having 			count(empno) > 1 group by deptno)
	where d.deptno = d1.deptno

2.列出薪水比’SMITH‘多的所有员工

SELECT * FROM EMP
       WHERE SAL > 
             (SELECT SAL FROM EMP WHERE ENAME = 'SMITH')

3.列出所有员工的姓名及其直接上级的姓名

SELECT E.ENAME AS EMPNAME, E1.ENAME AS MGRNAME FROM EMP E 
       JOIN EMP E1 ON E.MGR = E1.EMPNO

4.列出受雇日期早于其直接上级的所有员工

SELECT E.* FROM EMP E 
       JOIN EMP E1 ON E.MGR = E1.EMPNO
            WHERE E.HIREDATE > E1.HIREDATE

5.列出部门名称和这些部门的员工信息同时列出那些没有员工的部门

SELECT D.DNAME,D.DEPTNO, E.* FROM EMP E 
       RIGHT JOIN DEPT D ON E.DEPTNO = D.DEPTNO
       
-- left
select 
  d.deptno,d.dname,e.empno,e.ename 
from 
  dept d left join emp e
on
  d.deptno=e.deptno
-- Oracle 特殊用法 +
SELECT D.DNAME,D.DEPTNO, E.* FROM EMP E , DEPT D
	WHERE E.DEPTNO (+) = ED.DEPTNO
	
select 
  d.deptno,d.dname,e.empno,e.ename 
from 
  dept d ,emp e
where 
  d.deptno=e.deptno(+)

6.列出薪水大于1500的各种工作

SELECT JOB, MIN(SAL) FROM EMP
       GROUP BY JOB
            HAVING MIN(SAL) > 1500

7.列出在部门 ’SALES‘工作的员工姓名

SELECT ENAME FROM EMP
       WHERE DEPTNO = (SELECT DEPTNO FROM DEPT WHERE DNAME = 'SALES')
-- 2       
select 
  e.ename,d.dname 
from 
  emp e,dept d 
where 
  d.dname='SALES' 
  and 
  e.deptno=d.deptno

8.列出薪水高于公司平均薪水的所有员工

select ename,sal from emp where sal > (select avg(sal) from emp)

9.列出薪水等于30部门中员工的薪水的所有员工的姓名和薪水

select ename,sal,deptno from emp where sal in (select sal from emp where deptno = 30)

10.列出薪水高于在部门30工作的所有员工的薪水的员工姓名和薪水

select ename,sal,deptno from emp where sal > ALL(select sal from emp where deptno = 30)
-- 2
select 
  ename,sal 
from 
  emp 
where 
  sal>(select max(sal) from emp where deptno=30)

11.列出在每个部门工作的员工数量，平均工资和平均服务期限

SELECT DEPTNO, COUNT(*) AS 人数, AVG(SAL), AVG(SYSDATE - HIREDATE)
    FROM EMP
    GROUP BY DEPTNO

 select count(empno),round(avg(sal),2),round(avg(sysdate-hiredate)/365,0)
  from emp
  group by deptno

12.列出所有员工的姓名，部门名和工资

 select e.ename,d.dname,e.sal from emp e ,dept d where e.deptno = d.deptno;

13.列出所有部门的详细信息和部门人数

-- ...
SELECT D.DEPTNO,D.DNAME,D.LOC, E1.COU 人数
	FROM  DEPT D,(SELECT DEPTNO,COUNT(EMPNO) COU FROM EMP GROUP BY DEPTNO) E1
WHERE D.DEPTNO = E1.DEPTNO

14.列出各种工作的最低工资

select job, min(sal) from emp group by job;

15.列出各个部门的 ‘MANAGER’ 的最低薪水

select deptno, min(sal) from emp where job = 'MANAGER' group by deptno;

16.列出所有员工的年工资，按年薪从低到高排序

select ename, ((sal+NVL(COMM, 0)) * 12) year_sal from emp order by year_sal;

17.查询所有81年之后入职的员工信息

select * from emp 
    where to_char(hiredate, 'yyyy') > to_char(to_date('1981', 'yyyy'), 'yyyy');-- 按81年算的即82即之后年份入职的
-- select * from emp where hiredate > to_date('1981-01-01 00:00:00','YYYY-MM-DD HH24:MI:SS'); -- 按81年元月1日算的
 -- select * from emp where to_char(hiredate,'YYYY') > 81;

18.查询雇员表中，姓名为 ‘SMITH’ 的雇员，截至到今天共工作了多少周

select ROUND((sysdate - hiredate) / 7) from emp where ename = 'SMITH';

19.查询所有工作时间超过一年的员工编号

select empno from emp where to_char(sysdate,'YYYY') - to_char(hiredate,'YYYY') > 1 ;

20.查询今年十二月份倒数第二周周一是几号

select next_day((add_months(trunc(sysdate,'year'),12)-1) + (interval '-14' day),2) from dual;

标签：KAIFAMIAO,基于,--,练习,----------------------------,scott,emp,select,EMP
来源： https://blog.csdn.net/qq_43636709/article/details/120896185

基于scott做练习1

根据ER图创建表结构

使用上表完成数据查询

1.选择某一个部门的所有员工

2.列出所有第二级员工的姓名，编号，部门编号

3.找出奖金高于薪水的员工

4.找出奖金高于薪水60%的员工

5.找出部门某个部门的经理和某个部门的所有第二级员工的详细资料【两个部门不相同】

6.找出部门某个部门的经理，某个部门的所有第二级员工，既不是经理又不是办事员但其薪资小于或等于3000的员工的详细工作

7.找出收取奖金的员工的不同工作

8.找出不收取奖金或者奖金低于5000 的员工

9.找出各月倒数第三天受雇的所有员工

10.找出早于2年前受雇的员工

基于SCOTT 示例数据库进行练习

1.列出至少一个员工的所有部门

2.列出薪水比’SMITH‘多的所有员工

3.列出所有员工的姓名及其直接上级的姓名

4.列出受雇日期早于其直接上级的所有员工

5.列出部门名称和这些部门的员工信息 同时列出那些没有员工的部门

6.列出薪水大于1500的各种工作

7.列出在部门 ’SALES‘工作的员工姓名

8.列出薪水高于公司平均薪水的所有员工

9.列出薪水等于30部门中员工的薪水的所有员工的姓名和薪水

10.列出薪水高于在部门30工作的所有员工的薪水的员工姓名和薪水

11.列出在每个部门工作的员工数量，平均工资和平均服务期限

12.列出所有员工的姓名，部门名和工资

13.列出所有部门的详细信息和部门人数

14.列出各种工作的最低工资

15.列出各个部门的 ‘MANAGER’ 的最低薪水

16.列出所有员工的年工资，按年薪从低到高排序

17.查询所有81年之后入职的员工信息

18.查询雇员表中，姓名为 ‘SMITH’ 的雇员，截至到今天共工作了多少周

19.查询所有工作时间超过一年的员工编号

20.查询今年十二月份倒数第二周周一是几号

5.列出部门名称和这些部门的员工信息同时列出那些没有员工的部门