bzoj 3687 简单题——bitset
作者:互联网
题目:https://www.lydsy.com/JudgeOnline/problem.php?id=3687
关于 bitset :https://blog.csdn.net/snowy_smile/article/details/79120063
不知为何,上面的可以 A ,下面的会 WA 。
#include<cstdio> #include<cstring> #include<algorithm> #include<bitset> using namespace std; const int M=2e6+5; int n,s,ans; bitset<M> dp; int main() { scanf("%d",&n); dp[0]=1; for(int i=1,d;i<=n;i++) { scanf("%d",&d); dp^=(dp<<d); s+=d; } for(int i=1;i<=s;i++)if(dp[i])ans^=i; printf("%d\n",ans); return 0; }
#include<cstdio> #include<cstring> #include<algorithm> #include<bitset> using namespace std; const int N=1005,M=2e6+5; int n,a[N]; bitset<M> dp; int main() { scanf("%d",&n); for(int i=1;i<=n;i++)scanf("%d",&a[i]); dp[0]=1; int s=0; for(int i=1;i<=n;i++) dp^=(dp<<a[i]),s+=a[i]; int ans=0; for(int i=1;i<=s;i++)if(dp[i])ans^=i; printf("%d\n",ans); return 0; }
标签:int,2e6,3687,bitset,using,include,dp,bzoj 来源: https://www.cnblogs.com/Narh/p/10385736.html