1031 Hello World for U (20 分)

Given any string of N (≥5) characters, you are asked to form the characters into the shape of U. For example, helloworld can be printed as:

h  d
e  l
l  r
lowo

That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1​ characters, then left to right along the bottom line with n2​ characters, and finally bottom-up along the vertical line with n3​ characters. And more, we would like U to be as squared as possible -- that is, it must be satisfied that n1​=n3​=max { k | k≤n2​ for all 3≤n2​≤N } with n1​+n2​+n3​−2=N.

Input Specification:

Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

Output Specification:

For each test case, print the input string in the shape of U as specified in the description.

Sample Input:

helloworld!

结尾无空行

Sample Output:

h   !
e   d
l   l
lowor

结尾无空行

#include<iostream>
#include<cstring>
using namespace std;
int main()
{
    string a;
    cin>>a;
    int len=a.length()+2;
    int b=len/3;    //竖着的长度
    int i,j;
    j=len%3+b;      //最底下一层的长度
    int kong=j-2;
    for(i=0;i<b-1;i++)      //输出前b-1行的内容
    {
        cout<<a[i];
        for(int o=0;o<kong;o++){
            cout<<" ";
        }
        cout<<a[len-3-i]<<endl;
    }
    //输出最后一行
    for( i=b-1;i<=b+kong;i++)
    {
        cout<<a[i];
    }
}

标签：20,string,int,contains,characters,World,line,1031,n2
来源： https://blog.csdn.net/qq_52245648/article/details/120356647