leetcode 567 滑动窗口
作者:互联网
class Solution { public: bool checkInclusion(string s1, string s2) { unordered_map<char,int> need,window; for(char i: s1) { need[i]++; } int left=0; int right=0; int valid=0; while(right<s2.size()) { char c = s2[right]; right++; if(need.count(c)) { window[c]++; if(window[c]==need[c]) { valid++; } } while(right-left>=s1.size()) { if(valid==need.size()) { return true; } char l=s2[left]; left++; if(need.count(l)) { if(window[l]==need[l]) { valid--; } window[l]--; } } } return false; } };
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标签:int,s1,567,window,location,need,滑动,true,leetcode 来源: https://www.cnblogs.com/libin123/p/15175880.html