617.合并二叉树
作者:互联网
var mergeTrees = function (root1, root2) { if (root1 === null && root2 === null) return null; if (root1 === null && root2 !== null) return root2; if (root1 !== null && root2 === null) return root1; let root = new TreeNode(root1.val + root2.val); root.left = mergeTrees(root1.left, root2.left); root.right = mergeTrees(root1.right, root2.right); return root; };
标签:right,return,root,合并,617,二叉树,null,root1,root2 来源: https://www.cnblogs.com/guodandan/p/15065239.html