Vasya and Golden Ticket

原题链接
考察:双指针
思路:
  枚举和k,求\(sum[r]-sum[l]==k\)的最大r,注意特判0

Code

#include <iostream>
#include <cstring>
#include <algorithm>
using namespace std;
const int N = 110;
int n,sum[N];
char s[N];
bool check(int k)
{
	int l = 0,cnt = 0,r = 0;
	while(1)
	{
		while(r<=n&&sum[r]-sum[l]<=k) r++;
	    if(r-1==l||sum[r-1]!=sum[l]+k) return 0;
		l = r-1;
		cnt++;
		if(l==n&&cnt>1) return 1;
		else if(l==n&&cnt==1) return n>=2&&!k;
	}
}
int main()
{
	scanf("%d%s",&n,s+1);
	for(int i=1;i<=n;i++)
	{
		int x = s[i]-'0';
		sum[i] = sum[i-1]+x;
	}
	bool ok = 0;
	for(int k=0;k<=900;k++)
	{
	    if(!check(k)) continue;
	    ok = 1;
	}
	if(ok) puts("YES");
	else puts("NO");
	return 0;
}

标签：Vasya,cnt,return,Golden,int,sum,while,Ticket,include
来源： https://www.cnblogs.com/newblg/p/14985633.html