运算符重载-mstring迭代器
作者:互联网
实现代码:
#pragma once #ifndef MITERATOR_h #define MITERATOR_h //#include"mstring.h" class Mstring; class Miterator { private: Mstring* _p_mstr; int _sit; public: Miterator(Mstring* p_mstr, const int sit) { _p_mstr = p_mstr; _sit = sit; } Miterator(const Miterator& src) { _p_mstr = src._p_mstr; _sit = src._sit; } Miterator& operator++()//先自加,然后返回解引用this { ++_sit; return *this; } Miterator operator++(int)//后置不能返回引用 //要进行构造,拷贝构造要加const { return Miterator(_p_mstr, _sit++); } Miterator& operator--() { --_sit; return *this; } Miterator operator--(int) { return Miterator(_p_mstr, _sit--); } bool operator==(const Miterator& src)//确定指向同一个str,两个sit要相同 { if (_p_mstr == src._p_mstr && _sit == src._sit) { return true; } return false; } bool operator!=(const Miterator& src) { if (_p_mstr == src._p_mstr && _sit == src._sit) { return false; } return true; } char& operator*(); /* { return (*_p_mstr)[_sit]; } */ }; #endif
测试代码:
#include<iostream> #include<string> //#include"miterator.h" #include"mstring.h" using namespace std; /* namespace gg { typedef int Int; } */ int main() { #if 0 /* ++ -- != == * end(); begin(); */ string s1 = "abcdefg"; string::iterator it1 = s1.begin(); for (; it1 != s1.end(); it1++) { cout << *it1 << endl; } it1--; string::iterator it3 = it1; it1--; if (it1 == it3) { cout << "it1 == it3" << endl; } else { cout << "it1 != it3" << endl; } string s2 = "poiutyrr"; string::iterator it2 = s2.begin(); cout << s2 << endl; cout << *it2 << endl; *it2 = 'm'; cout << *it2 << endl; /* if (it1 == it2) { cout << "it1 = it 2" << endl;; } else { cout << "it1 != it2" << endl; }*/ #endif Mstring str1 = "1234567"; Mstring::miterator its1 = str1.begin(); for (; its1 != str1.end(); its1++) { (*its1)++; cout << *its1 << endl; } return 0; }
标签:mstring,return,迭代,Miterator,sit,mstr,运算符,operator,src 来源: https://www.cnblogs.com/xpei-1124/p/14864308.html