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预算分配Budget Allocation:Morphl-AI的营销科学解决方案(一)

作者:互联网

文章目录


1 公司介绍

Morphl是一家国外提供AI解决方案的公司(PS:这家公司,web UI挺好看的~):
网址:https://morphl.io/products/morphl-cloud.html
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MorphL社区版
MorphL Community Edition使用大数据和机器学习来预测数字产品和服务中的用户行为,其目标是通过个性化来提高KPI(点击率,转换率等),主要涵盖的模型包括:


2 预算分配

在morphl理论体系里面,预算分配包含两个步骤:

第一步 预算/收入预测函数

f(Cost) = f(Cost(t) | Cost(t-1), Revenue(t-1), ... Cost(t0), Revenue(t0)) = Revenue function

根据历史的预算/收入数据,进行预测

第二步 预算最优化问题
在有了每个活动预算/收入预测函数之后,就可以开始解决预算最优化,以下有三种情况:
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黄线是预算/投入金额累计线;
蓝线是预算/投入效率曲线(原文表示:The blue line is the relation between the budget and the returning sum.

曲线的顶点就是最佳的budge范围,可以帮助进行预算分配

3 相关案例解读

3.1 相关数据样式

github地址:Morphl-AI/Ecommerce-Marketing-Spend-Optimization

来看github放开的两个数据源格式:

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其中的几个案例,介绍了几种他们常用的方法:

3.2 2. Budget optimization - basic statistical model

这里其实是非常简单的几种方法

3.3 4. Budget allocation - pseudo-revenue - first-revenue assumption - regressions

Let a bucket be: C o s t B = [ 0 , 0 , 50 , 20 , 0 , 15 ] Cost_B=[0, 0, 50, 20, 0, 15] CostB​=[0,0,50,20,0,15], R e v e n u e B = [ 30 , 100 ] Revenue_B=[30, 100] RevenueB​=[30,100].
This means that the first revenue (30) was generated by the first two costs alone,
so we merged the next bucket as well.
We’ll sum them, getting C Σ B = 85 C_{\Sigma B}=85 CΣB​=85 and R Σ B = 130 R_{\Sigma B}=130 RΣB​=130. Then, the bucket constant is: α B = 130 / 85 = 1.529 \alpha_B=130/85=1.529 αB​=130/85=1.529.
Then, our pseudo-revenues will be: P s e u d o − R e v e n u e B = [ 0 ∗ α B , 0 ∗ α B , 50 ∗ α B , 20 ∗ α B , 0 ∗ α B , 15 ∗ α B ] = [ 0 , 0 , 76.45 , 30.58 , 0 , 22.935 ] Pseudo-Revenue_{B} = [0*\alpha_B, 0*\alpha_B, 50*\alpha_B, 20*\alpha_B, 0*\alpha_B, 15*\alpha_B] = [0, 0, 76.45, 30.58, 0, 22.935] Pseudo−RevenueB​=[0∗αB​,0∗αB​,50∗αB​,20∗αB​,0∗αB​,15∗αB​]=[0,0,76.45,30.58,0,22.935].

借助上述例子,猜测,

3.4 5. Budget allocation - pseudo-revenue - one-week assumption - regressions

第四案例,可能是间断式的活动,那么第五个案例,可能是一个长期的案例,
所以这里的bucket时间间隔是固定的1周,以此进行计算。


4 代码测试

github地址:Morphl-AI/Ecommerce-Marketing-Spend-Optimization

来看github放开的两个数据源格式:

4.1 简单系数一阶收入预测

对应jupyter - 2. Budget optimization - basic statistical model

就是直接 => R e v / C o s t Rev / Cost Rev/Cost

import pandas as pd

'''
模型一:直接算个总的ROI
Directly modeling f(Cost) = Revenue
'''
class StatisticalModel:
    def __init__(self):
        # This model has just a single parameter, computed as the count between targets and inputs
        self.param = np.nan
        
    def fit(self, x, t):
        assert self.param != self.param
        self.param = t.sum() / x.sum()  # 核心,非常简单的算一个ROI,作为系数进行计算
    
    def predict(self, x):
        assert self.param == self.param
        return x * self.param
    
def errorL1(y, t):
    return np.abs(y - t).mean()

def plot(model, valData, xKey, tKey):
    validCampaigns = list(valData.keys())
    ax = plt.subplots(len(validCampaigns), figsize=(5, 30))[1]
    for i, k in enumerate(validCampaigns):
        x = valData[k][xKey]
        t = valData[k][tKey]
        y = model[k].predict(x)
        ax[i].scatter(x, y, label="%s Predicted" % (tKey))
        ax[i].scatter(x, t)
        ax[i].set_title(k)
        ax[i].legend()

# 数据读入

conversion_data = pd.read_csv('Datasets/conversion_data.csv')
# marketing_spend_data = pd.read_csv('Datasets/marketing_spend_data.csv')


model_cost_revenue = {}
predictions_cost_revenue = {}
errors_cost_revenue = {}
displayDf = pd.DataFrame()
res_cost_revenue = []

campaigns = set(conversion_data['xyz_campaign_id'])
# from sklearn.model_selection import train_test_split
# X_train,X_test,y_train,y_test = train_test_split(iris.data,iris.target,test_size=0.3,random_state=0)
trainData = {}
valData = {}
for k in campaigns:
    data = conversion_data[conversion_data['xyz_campaign_id'] == k]
    num = int(len(data)*0.8)
    trainData[k] = data[:num]
    valData[k] = data[num:]

# Cost_col = 'Cost'
# Revenue_col = 'Revenue'
Cost_col = 'Spent'  # 投入
Revenue_col = 'Total_Conversion' # 产出

for k in campaigns:
    model_cost_revenue[k] = StatisticalModel()
    model_cost_revenue[k].fit(trainData[k][Cost_col], trainData[k][Revenue_col])
    predictions_cost_revenue[k] = model_cost_revenue[k].predict(valData[k][Cost_col])
    errors_cost_revenue[k] = errorL1(predictions_cost_revenue[k], valData[k][Revenue_col])
    res_cost_revenue.append([k, trainData[k][Cost_col].sum(), trainData[k][Revenue_col].sum(), \
                model_cost_revenue[k].param, errors_cost_revenue[k]])


displayDf = pd.DataFrame(res_cost_revenue, columns=["Campaign", Cost_col, Revenue_col, "Fit", "Error (L1)"])
display(displayDf)
print("Mean error:", displayDf["Error (L1)"].mean())

plot(model_cost_revenue, valData, Cost_col, Revenue_col)

只是一个范例,
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4.2 模型二:考虑曝光

类似:cost -> 曝光 -> 收入

Cost x Revenue ~= Cost x Sessions + Sessions x Revenue

曝光 = a1 * cost
收入 = a2 * 曝光

分两步走,主要截取的也是2. Budget optimization - basic statistical model

# 随机设定一个session
session_col = 'Impressions' # 曝光
Cost_col = 'Spent'  # 投入
Revenue_col = 'Total_Conversion' # 产出

# 第一步:曝光 = a1 * cost
model_cost_sessions = {}
predictions_cost_sessions = {}
errors_cost_sessions = {}
displayDf = pd.DataFrame()
res_cost_sessions = []
for k in campaigns:
    model_cost_sessions[k] = StatisticalModel()
    model_cost_sessions[k].fit(trainData[k][Cost_col], trainData[k][session_col])
    predictions_cost_sessions[k] = model_cost_sessions[k].predict(valData[k][Cost_col])
    errors_cost_sessions[k] = errorL1(predictions_cost_sessions[k], valData[k][session_col])
    res_cost_sessions.append([k, trainData[k][Cost_col].sum(), trainData[k][session_col].sum(), \
                model_cost_sessions[k].param, errors_cost_sessions[k]])

displayDf = pd.DataFrame(res_cost_sessions, columns=["Campaign", Cost_col, session_col, "Fit", "Error (L1)"])
display(displayDf)
print("Mean error:", displayDf["Error (L1)"].mean())

plot(model_cost_sessions, valData, Cost_col, session_col)

# 第二步:收入 = a2 * 曝光
model_sessions_revenue = {}
predictions_sessions_revenue = {}
errors_sessions_revenue = {}
displayDf = pd.DataFrame()
res_sessions_revenue = []
for k in campaigns:
    model_sessions_revenue[k] = StatisticalModel()
    model_sessions_revenue[k].fit(trainData[k][session_col], trainData[k][Revenue_col])
    predictions_sessions_revenue[k] = model_sessions_revenue[k].predict(valData[k][session_col])
    errors_sessions_revenue[k] = errorL1(predictions_sessions_revenue[k], valData[k][Revenue_col])
    res_sessions_revenue.append([k, trainData[k][session_col].sum(), trainData[k][Revenue_col].sum(), \
                model_sessions_revenue[k].param, errors_sessions_revenue[k]])

displayDf = pd.DataFrame(res_sessions_revenue, columns=["Campaign", session_col, Revenue_col, "Fit", "Error (L1)"])
display(displayDf)
print("Mean error:", displayDf["Error (L1)"].mean())

plot(model_sessions_revenue, valData, session_col, Revenue_col)

# 第三步:合并
displayDf = pd.DataFrame()
errors_cost_revenue = {}
res_cost_revenue_combined = []

class TwoModel(object):
    def __init__(self, modelA, modelB):
        self.modelA = modelA
        self.modelB = modelB
    
    def predict(self, x):
        return self.modelA.predict(self.modelB.predict(x))
models_cost_revenue = {k : TwoModel(model_cost_sessions[k], model_sessions_revenue[k]) for k in valData}

for k in campaigns:
    predictions_cost_revenue[k] = models_cost_revenue[k].predict(valData[k][Cost_col])
    errors_cost_revenue[k] = errorL1(predictions_cost_revenue[k], valData[k][Revenue_col])
    res_cost_revenue_combined.append([k, errors_cost_revenue[k]])

displayDf = pd.DataFrame(res_cost_revenue_combined, columns=["Campaign", "Error (L1)"])
display(displayDf)
print("Mean error:", displayDf["Error (L1)"].mean())


plot(models_cost_revenue, valData, Cost_col, Revenue_col)

标签:revenue,AI,sessions,Morphl,Budget,cost,model,col,Cost
来源: https://blog.csdn.net/sinat_26917383/article/details/117663751