Linux下快速拷贝单个大文件的秘诀
作者:互联网
#include <stdio.h>
#include <unistd.h>
#include <fcntl.h>
#include <stdlib.h>
#include <string.h>
#include <sys/mman.h>
#include <sys/stat.h>
#include <sys/wait.h>
void err_int(int ret, const char *err)
{
if (ret == -1) {
perror(err);
exit(1);
}
return ;
}
void err_str(char *ret, const char *err)
{
if (ret == MAP_FAILED) {
perror(err);
exit(1);
}
}
int main(int argc, char *argv[])
{
int fd_src, fd_dst, ret, len, i, n;
char *mp_src, *mp_dst, *tmp_srcp, *tmp_dstp;
pid_t pid;
struct stat sbuf;
if (argc < 3 || argc > 4) {
printf("使用方法: ./script src_file dest_file\n");
printf("例子: ./copy a.file /vdb/a.file\n");
exit(1);
} else if (argc == 3) {
n = 5;
} else if (argc == 4) {
n = atoi(argv[3]);
}
fd_src = open(argv[1], O_RDONLY);
err_int(fd_src, "open dict.txt err");
fd_dst = open(argv[2], O_RDWR | O_CREAT | O_TRUNC, 0664);
err_int(fd_dst, "open dict.cp err");
ret = fstat(fd_src, &sbuf);
err_int(ret, "fstat err");
len = sbuf.st_size;
if (len < n)
n = len;
ret = ftruncate(fd_dst, len);
err_int(ret, "truncate fd_dst err");
mp_src = (char *)mmap(NULL, len, PROT_READ, MAP_SHARED, fd_src, 0);
err_str(mp_src, "mmap src err");
mp_dst = (char *)mmap(NULL, len, PROT_READ | PROT_WRITE, MAP_SHARED, fd_dst, 0);
err_str(mp_dst, "mmap dst err");
tmp_dstp = mp_dst;
tmp_srcp = mp_src;
int bs = len / n;
int mod = len % bs;
for (i = 0; i < n; i++) {
if ((pid = fork()) == 0) {
break;
}
}
if (n == i) {
for (i = 0; i < n; i++)
wait(NULL);
} else if (i == (n-1)){
memcpy(tmp_dstp+i*bs, tmp_srcp+i*bs, bs+mod);
} else if (i == 0) {
memcpy(tmp_dstp, tmp_srcp, bs);
} else {
memcpy(tmp_dstp+i*bs, tmp_srcp+i*bs, bs);
}
munmap(mp_src, len);
munmap(mp_dst, len);
return 0;
}
将上面文件保存为copy.c,使用方法:
gcc copy.c -o copy
./copy src_file dest/src_file
标签:src,err,int,dst,len,fd,Linux,拷贝,秘诀 来源: https://www.cnblogs.com/dykstudy/p/15415366.html