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需要有关mysql规范化和php类结构的建议

作者:互联网

我正在尝试建立一个记录日志,媒体(照片,视频,音频)上传统计信息的系统.所以我想出3张桌子,1张用于音频,1张用于视频,1张用于照片.这是结构

+-----------+---------+------+-----+---------+----------------+
| Field     | Type    | Null | Key | Default | Extra          |
+-----------+---------+------+-----+---------+----------------+
| id        | int(11) | NO   | PRI | NULL    | auto_increment |
| member_id | int(10) | NO   |     | NULL    |                |
| counter   | int(11) | NO   |     | NULL    |                |
| daydate   | text    | NO   |     | NULL    |                |
| epochtime | text    | NO   |     | NULL    |                |
+-----------+---------+------+-----+---------+----------------+

这三个表都具有相同的字段,因为我认为(到目前为止)我需要区分每个表和特定表上的媒体,这是否多余?

无论如何,由于每种媒体都被视为相同,所以我认为我应该只建立一次类,并根据当时访问的媒体使用某种方法.这是课程:

require_once(INC_PATH.DS.'database.php');

    class Log extends DatabaseObject {

        protected static $db_fields = array('id', 'member_id', 'counter',  'daydate', 'epochtime');

        public $id;
        public $member_id;
        public $counter;
        public $daydate;
        public $epochtime;

        public function find_counter($table_name){
            global $database;
            $time = date('d-m-Y');
            $timestamp = time();

            $sql  = "SELECT * FROM ". $table_name;
            $sql .= " WHERE daydate = '".$this->daydate."'";            
            $sql .= " AND member_id = '".$this->member_id."'";

            return self::find_by_sql($sql);
        }

        public function add_log($table_name){
            global $database;
            $tes = $this->find_counter();

            if(!empty($tes)){
                $sql  = "UPDATE ".$table_name;
                $sql .= " SET counter = counter+1";
                $sql .= " WHERE daydate = '".$this->daydate."'";
                $sql .= " AND member_id = '".$this->member_id."'";

                $database->query($sql);
                return ($database->affected_rows() == 1) ? true : false;
            }else{

                $sql  = "INSERT INTO ".$table_name;
                $sql .= " (id, member_id, user_privelege, counter, daydate, epochtime)";
                $sql .= " VALUES ('', '".$this->member_id."'";
                $sql .= " , '".$this->user_privelege."', '1', '".$this->daydate."', '".$this->epochtime;
                $sql .= "')";

                $database->query($sql);
                return ($database->affected_rows() == 1) ? true : false;
            }
        }

  }

到目前为止,这几乎可以正常工作,但是,我仍然对将表拆分为3个表的方式以及使用$table_name作为参数的方式仍存疑问.任何更好的建议?我真的很想改善我的代码,非常感谢

问候

更新

好了,根据大家的回答,我想澄清一下:

>我只需要记录上传的媒体
>我已经有了另一个单独的表来记录每种媒体的其他信息(长度,文件名,标题等).

可以说我添加了一个名为“ media_id”的字段并将表合并为一个字段,由于我添加和更新行的方式基于日期,因此如果找不到给定的日期和member_id,它将插入,否则它将更新,我想我也应该将add_log()方法的工作方式更改为:

public function add_log($table_name, $media_id){
    global $database;
    $tes = $this->find_counter();

    if(!empty($tes)){
        $sql  = "UPDATE ".$table_name;
        $sql .= " SET counter = counter+1";
        $sql .= " WHERE daydate = '".$this->daydate."'";
        $sql .= " AND member_id = '".$this->member_id."'";
        $sql .= " AND media_id = '".$media_id."'";

        $database->query($sql);
        return ($database->affected_rows() == 1) ? true : false;
    }else{

        $sql  = "INSERT INTO ".$table_name;
        $sql .= " (id, member_id, media_id, counter, daydate, epochtime)";
        $sql .= " VALUES ('', '".$this->member_id."'";
        $sql .= " , '".$media_id."', '1', '".$this->daydate."', '".$this->epochtime;
        $sql .= "')";

        $database->query($sql);
        return ($database->affected_rows() == 1) ? true : false;
    }
}

你们有什么感想 ??

再次感谢

解决方法:

将它们全部放在一个表中,并具有一个media_type列.

+-----------+---------+------+-----+---------+----------------+
| Field     | Type    | Null | Key | Default | Extra          |
+-----------+---------+------+-----+---------+----------------+
| id        | int(11) | NO   | PRI | NULL    | auto_increment |
| member_id | int(10) | NO   |     | NULL    |                |
| counter   | int(11) | NO   |     | NULL    |                |
| daydate   | text    | NO   |     | NULL    |                |
| epochtime | text    | NO   |     | NULL    |                |
| media_type| int     | NO   |     | NULL    |                |
+-----------+---------+------+-----+---------+----------------+

创建与另一个定义media_type的表的外键关系.

+-----------+---------+------+-----+---------+----------------+
| Field        | Type | Null | Key | Default | Extra          |
+-----------+---------+------+-----+---------+----------------+
| media_type_id| int  | NO   | PRI | NULL    |                |
| description  | text | NO   |     | NULL    |                |
 +-----------+---------+------+-----+---------+----------------+

这将保存media_type_id(例如1)和media_type_description(例如音频).
例如

1, audio
2, video
3, photo

然后,主表将仅在每一行上包含ID 1、2、3,以表示它是哪种媒体类型.然后,您可以在应用程序中使用此功能通过WHERE子句进行约束,即您所指的是哪种媒体.例如从主表中选择* WHERE media_type_id = 3即可获取照片.

标签:normalization,class-design,mysql,php,database
来源: https://codeday.me/bug/20191105/1996734.html