php-从数据库表创建数组“树”
作者:互联网
我的PHP功能
function generateMenu($parent, $level, $menu, $utype) {
global $db;
$tree = array();
$stmt = $db->prepare("select id, parent, name FROM navigation WHERE menu=? AND user_type=?") or die($db->error);
$stmt->bind_param("ii", $menu, $utype) or die($stmt->error);
$stmt->execute() or die($stmt->error);
$stmt->store_result();
$meta = $stmt->result_metadata();
$stmt->bind_result($id, $parent, $name);
while ($stmt->fetch()) {
$arr[$id] = array(
'name' => $name,
'parent' => $parent
);
if (!array_key_exists($parent,$arr) and $parent != 0) {
$arr[$parent][$id] = $id;
}
}
$stmt->close();
}
从数据库表生成以下数组. [1],[2] …-是li项目的ID
Array (
[1] => Array (
[name] => Parent1
[parent] => 0
)
[2] => Array (
[name] => Parent2
[parent] => 0
)
[3] => Array (
[name] => Parent3
[parent] => 0
)
[4] => Array (
[name] => Child1 of P1
[parent] => 1
)
[5] => Array (
[name] => Child2 of P1
[parent] => 1
)
)
我想要做的就是像这样创建菜单
<ul>
<li><a href="?page=1">Parent1</a>
<ul>
<li><a href="?page=4">Child1 of P1</a></li>
...
第二个功能是从该数组生成菜单.但是我知道在将该数组发送到第二个函数之前,我需要将其转换为多维树数组.我不知道该怎么做.
这是第二个功能
function olLiTree($tree) {
$out = '<ul>';
foreach($tree as $key => $value) {
$out.= '<li>';
if (is_array($value)) {
$out.= $key . olLiTree($value);
} else {
$out.= $value;
}
$out.= '</li>';
}
$out.= '</ul>';
return $out;
}
db结构
解决方法:
函数array_key_exists()
需要两个参数,您只能传递一个.我想你的意思是:
while(list($id, $parent, $name) = mysql_fetch_assoc($results)) {
$tree[$id] = array(
'name' => $name,
'children' => array(),
'parent' => $parent
);
if (!array_key_exists($parent,$tree)) {
$tree[$parent]['children'][$id] = $id;
}
}
您更改了答案,所以我认为问题不在于array_keys_exists.无论如何,您都可以尝试使用这种方式通过MaxDB获取数据:
function generateMenu($parent, $level, $menu, $utype) {
global $db;
$tree = array();
$stmt = $db->prepare("select id, parent, name FROM navigation WHERE menu=? AND user_type=?") or die($db->error);
$stmt->bind_param("ii", $menu, $utype) or die($stmt->error);
$stmt->execute() or die($stmt->error);
$stmt->store_result();
$meta = $stmt->result_metadata();
$stmt->bind_result($id, $parent, $name);
while ($stmt->fetch()) {
$tree[$id] = array(
'name' => $name,
'children' => array(),
'parent' => $parent
);
if (!array_key_exists($parent,$tree)) {
$tree[$parent]['children'][$id] = $id;
}
}
$stmt->close();
print_r($tree);
}
对于第二个功能,我认为@jeroen具有严格性,您需要使用this anwser.
标签:tree,hierarchical-data,arrays,mysql,php 来源: https://codeday.me/bug/20191102/1987866.html