sql-Create语句中的变量
作者:互联网
我正在尝试在创建脚本中使用一些变量进行数据库设置.我不确定如何使用它们.请说明如何正确格式化我的代码.以下是我尝试的代码以及出现的错误:
SET @username = 'xxxx'; -- store number goes here
SET @password = 'xxxxxx'; -- store password goes here
CREATE TABLE IF NOT EXISTS `my_table` (
`id` int(11) auto_increment,
`release_date` datetime,
`front_image_file` varchar(255),
PRIMARY KEY (`id`)
) ENGINE=FEDERATED
DEFAULT CHARSET=latin1
AUTO_INCREMENT=1
CONNECTION='mysql://`@username`:`@password`@host_name:3306/database_name/table_tame' ;
错误
#1432 - Can't create federated table. The data source connection string 'mysql://`@username`:`@password`@host_name:3306/databa' is not in the correct format
我也尝试了没有`
尝试EdmundG的解决方案
SET @username = 'xxxx'; -- store number goes here
SET @password = 'xxxxxx'; -- store password goes here
CREATE TABLE IF NOT EXISTS `my_table` (
`id` int(11) auto_increment,
`release_date` datetime,
`front_image_file` varchar(255),
PRIMARY KEY (`id`)
) ENGINE=FEDERATED
DEFAULT CHARSET=latin1
AUTO_INCREMENT=1
CONNECTION='Uid=@username; Pwd=@password; Server=****; Port=3306; Database =****; Table=****;' ;
没用,仍然说格式不正确
解决方法:
MySQL不支持将变量插值直接插入这样的语法中.
但是,您可以使用这些变量构建一个字符串,然后将其准备并执行为dynamic SQL.
SET @username = 'xxxx'; -- store number goes here
SET @password = 'xxxxxx'; -- store password goes here
SET @sql = CONCAT('CREATE TABLE IF NOT EXISTS `my_table` (',
' `id` int(11) auto_increment,',
' `release_date` datetime,',
' `front_image_file` varchar(255),',
' PRIMARY KEY (`id`)',
') ENGINE=FEDERATED',
' DEFAULT CHARSET=latin1',
' AUTO_INCREMENT=1',
' CONNECTION=''mysql://', @username, ':', @password,
'@host_name:3306/database_name/table_tame');
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE stmt;
标签:variables,connection,sql,mysql,federated 来源: https://codeday.me/bug/20191024/1920439.html