在PHP / MySQL中使用Week(Date)时,如何将一周的第一天设置为星期一?
作者:互联网
我正在使用以下代码构建Google图表,以提取与一年中的周数相对应的MySQL表中的所有条目.目前,周号从星期日开始,我想更改此值,以便它们从星期一开始,但是我不确定如何执行此操作.
$i=1;
while($i<=53)
{
$week_start = new DateTime();
$week_start->setISODate(2013,$i+1);
$date_display = $week_start->format('j M Y');
$sessions = $wpdb->get_var($wpdb->prepare("SELECT Sum(Due) from patient_sessions WHERE Type='Session' AND Week(Date)='$i'"));
$temp = array();
$temp[] = array('v' => (string) $date_display);
$temp[] = array('v' => (string) $sessions);
$rows[] = array('c' => $temp);
$i++;
}
修改后的代码
$sessions = $wpdb->get_results($wpdb->prepare("SELECT Due,Date from patient_sessions WHERE Type='Session'"));
$work_times = $wpdb->get_results($wpdb->prepare("SELECT Amount,Date from work_times"));
$expenses = $wpdb->get_results($wpdb->prepare("SELECT Amount,Date from expenses WHERE Client='Psychotherapy'"));
$i=1;
while($i<=53) {
$week_start = new DateTime();
$week_start->setISODate(2013,$i+1);
$date_display = $week_start->format('j M Y');
$session_total = 0;
$work_time_total = 0;
$expense_total = 0;
foreach ($sessions as $session) {
if (date("W", strtotime($session->Date)) == $i) {
$session_total = ($session_total+$session->Due);
}
}
foreach ($work_times as $work_time) {
if (date("W", strtotime($work_time->Date)) == $i) {
$work_time_total = ($work_time_total+$work_time->Amount);
}
}
foreach ($expenses as $expense) {
if (date("W", strtotime($expense->Date)) == $i) {
$expense_total = ($expense_total+$expense->Amount);
}
}
$balance = ($session_total + $work_time_total - $expense_total);
$temp = array();
$temp[] = array('v' => (string) $date_display);
$temp[] = array('v' => (string) $balance);
$rows[] = array('c' => $temp);
$i++;
}
解决方法:
WEEK(date[mode]);
date = a date value.
mode = An integer indicating the starting of the week.
默认arugment为0,即星期日,将其设置为1将是星期一,2星期二,依此类推.
week(date,1);
标签:php,mysql,date,week-number 来源: https://codeday.me/bug/20191012/1897439.html