数据库特殊用法
作者:互联网
//质量之星 select b.user_name as userName, c.expert_id as expertId, b.user_photo as userHeadIcon, amout as codeSum, rn as rank from user_info b,( select expert_id,amout,row_number() over(order by amout desc) as rn from( select expert_id, count(expert_id) amout from code_infos a group by a.expert_id ) ) c where b.user_id = c.expert_id and c.rn <= 50;
//
with sql0 as (SELECT USER_NAME, USER_ID FROM USER_INFO), sql1 as (SELECT APPROVE_FLOW_ID ,ASSET_TYPE ,ASSET_ID, APPLI_OPERATOR ,CREATED_DT ,APPLI_OPINION FROM ASSET_APPROVE_LOGS WHERE APPROVE_FLOW_ID = :approveFlowId AND PROCESS_ID = :processId), sql2 as (SELECT PROJECT_ID, PROJECT_LABEL, DOMAIN_CODE ,PROJECT_NAME ,PROJECT_DESC ,RELEASE_TIME ,STATUS FROM MODEL_PROJECT_INFO WHERE APPROVE_FLOW_ID = :approveFlowId), sql3 as (SELECT DOMAIN_NAME, DOMAIN_CODE FROM ASSET_DOMAIN_INFOS) select sql0.USER_NAME AS userName, sql1.APPROVE_FLOW_ID AS approveFlowId, DECODE(sql1.ASSET_TYPE, 'A00001', '模型', 'A00002', '专题', 'A00003', '指标', 'A00004', '标签', 'A00005', '代码') AS assetType, sql1.ASSET_ID AS assetId, sql1.CREATED_DT AS appliTime, sql1.APPLI_OPINION AS appliOpinion, sql2.PROJECT_NAME AS assetName, sql2.PROJECT_DESC AS assetDesc, sql2.RELEASE_TIME AS releaseTime, DECODE(sql2.STATUS, '0', '草稿', '1', '待审核', '2', '已发布', '3', '已下线', '4', '被驳回', '5', '被退回', '6', '已下发', '7', '已删除') AS assetStatus, sql3.DOMAIN_NAME AS domainName, sql2.PROJECT_LABEL AS assetLabel from sql0 join sql1 on sql0.USER_ID = sql1.APPLI_OPERATOR join sql2 on sql1.ASSET_ID = sql2.PROJECT_ID join sql3 on sql2.DOMAIN_CODE = sql3.DOMAIN_CODE
//marge into的用法
//start with的用法
标签:DOMAIN,特殊,sql1,数据库,ID,PROJECT,ASSET,用法,sql2 来源: https://blog.csdn.net/a5575vhj/article/details/88744218