mysql8.0设置简单密码报错ERROR : Your password does not satisfy the current policy requirements
作者:互联网
【原因】
原来MySQL5.6.6版本之后增加了密码强度验证插件validate_password,相关参数设置的较为严格。
使用了该插件会检查设置的密码是否符合当前设置的强度规则,若不满足则拒绝设置。影响的语句和函数有:create user,grant,set password,password(),old password。
【解决】
1) 查看mysql全局参数配置
该问题其实与mysql的validate_password_policy的值有关。
查看一下msyql密码相关的几个全局参数:
mysql> select @@validate_password_policy; +----------------------------+ | @@validate_password_policy | +----------------------------+ | MEDIUM | +----------------------------+ 1 row in set (0.00 sec) mysql> SHOW VARIABLES LIKE 'validate_password%'; +--------------------------------------+--------+ | Variable_name | Value | +--------------------------------------+--------+ | validate_password.dictionary_file | | | validate_password.length | 8 | | validate_password.mixed_case_count | 1 | | validate_password.number_count | 1 | | validate_password.policy | MEDIUM | | validate_password.special_char_count | 1 | +--------------------------------------+--------+ 6 rows in set (0.08 sec)
2)参数解释
validate_password.dictionary_file
插件用于验证密码强度的字典文件路径。
validate_password.length
密码最小长度,参数默认为8,它有最小值的限制,最小值为:validate_password_number_count + validate_password_special_char_count + (2 * validate_password_mixed_case_count)
validate_password.mixed_case_count
密码至少要包含的小写字母个数和大写字母个数。
validate_password.number_count
密码至少要包含的数字个数。
validate_password.policy
密码强度检查等级,0/LOW、1/MEDIUM、2/STRONG。有以下取值:
Policy Tests Performed
0 or LOW Length
1 or MEDIUM Length; numeric, lowercase/uppercase, and special characters
2 or STRONG Length; numeric, lowercase/uppercase, and special characters; dictionary file
默认是1,即MEDIUM,所以刚开始设置的密码必须符合长度,且必须含有数字,小写或大写字母,特殊字符。
validate_password.special_char_count
密码至少要包含的特殊字符数。
3)修改mysql参数配置
mysql> set global validate_password.policy=0; Query OK, 0 rows affected (0.05 sec) mysql> mysql> mysql> set global validate_password.mixed_case_count=0; Query OK, 0 rows affected (0.00 sec) mysql> set global validate_password.number_count=3; Query OK, 0 rows affected (0.00 sec) mysql> set global validate_password.special_char_count=0; Query OK, 0 rows affected (0.00 sec) mysql> set global validate_password.length=3; Query OK, 0 rows affected (0.00 sec) mysql> SHOW VARIABLES LIKE 'validate_password%'; +--------------------------------------+-------+ | Variable_name | Value | +--------------------------------------+-------+ | validate_password.dictionary_file | | | validate_password.length | 3 | | validate_password.mixed_case_count | 0 | | validate_password.number_count | 3 | | validate_password.policy | LOW | | validate_password.special_char_count | 0 | +--------------------------------------+-------+ 6 rows in set (0.00 sec)
4)修改密码:
ALTER USER 'root'@'localhost' IDENTIFIED WITH mysql_native_password BY 'new-password'; Query OK, 0 rows affected, 1 warning (0.00 sec)
OK了。
标签:satisfy,count,set,requirements,报错,mysql,sec,validate,password 来源: https://www.cnblogs.com/liweikuan/p/15003759.html