题目要求

1. 按照’月份‘排序

select *,row_number() over (partition by continent order by name) rn from students;

2.行列转换，找出符合条件的一个人

select  
min(
case when continent = '一月' then name else  end)  as 一月,
min(
case when continent = '二月' then name else null end)  as 二月,
min(
case when continent = '三月' then name else null end)  as 三月,
min(
case when continent = '四月' then name else null end)  as 四月
from students;

3. 汇总集合

select  
min(
case when continent = '一月' then name else null end)  as 一月,
min(
case when continent = '二月' then name else null end)  as 二月,
min(
case when continent = '三月' then name else null end)  as 三月,
min(
case when continent = '四月' then name else null end)  as 四月
from (
select *,row_number() over (partition by continent order by name) rn from students
) b
group by rn;

标签：地理信息,end,name,min,when,618,LeetCode,else,continent
来源： https://www.cnblogs.com/Tdazheng/p/14962640.html