python EDS加密和弱密钥验证
作者:互联网
import math
import numpy as np
from pyDes import *
pc1 = [56, 48, 40, 32, 24, 16, 8,
0, 57, 49, 41, 33, 25, 17,
9, 1, 58, 50, 42, 34, 26,
18, 10, 2, 59, 51, 43, 35,
62, 54, 46, 38, 30, 22, 14,
6, 61, 53, 45, 37, 29, 21,
13, 5, 60, 52, 44, 36, 28,
20, 12, 4, 27, 19, 11, 3
]
pc2 = [
13, 16, 10, 23, 0, 4,
2, 27, 14, 5, 20, 9,
22, 18, 11, 3, 25, 7,
15, 6, 26, 19, 12, 1,
40, 51, 30, 36, 46, 54,
29, 39, 50, 44, 32, 47,
43, 48, 38, 55, 33, 52,
45, 41, 49, 35, 28, 31
]
left_rotations = [
1, 1, 2, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 2, 1
]
def create_sub_keys(a):
print("密钥:",a)
k=bin(int(a,16))
k=k.split("b")[-1]
while(len(k)<64):
k='0'+k
print("补全:",k)
key=[]
for l in range(16):
sub=""
subk=""
for i in range(56):
subk+=k[pc1[i]]
kl=subk[0:28]
kr=subk[28:]
kl=kl[left_rotations[l]:]+kl[0:left_rotations[l]]
kr=kr[left_rotations[l]:]+kr[0:left_rotations[l]]
subk=kl+kr
for j in range(48):
sub+=subk[pc2[j]]
key.append(sub)
print("48位:\n",np.array(key))
return
def desEncrypt(key=b"DESCRYPT",data = b"This message will be encrypted."):
while(len(data)%8!=0):
data+=b'a'
# t=des(key, CBC, "\0\0\0\0\0\0\0\0")
t=des(key)
mi=t.encrypt(data)
again=t.encrypt(mi)
ming=t.decrypt(mi)
print("数据:",data)
print("密钥:",key)
print("密文:",mi)
print("密文再加密:",again)
print("明文:",ming)
if __name__=="__main__":
a=b"DESCRYPT"
keyList=[
"0101010101010101",
"1F1F1F1F0F0F0E0E",
"E0E0E0E0F1F1F1F1",
"FEFEFEFEFEFEFEFE",
"01FE01FE01FE01FE",
"01E001E001F101F1",
"FE01FE01FE01FE01",
"E001E001F101F101"
]
for i in keyList:
create_sub_keys(i)
desEncrypt(bytes.fromhex(i))
print("\n\n")
desEncrypt(a)
key=input("\n\n请输入8个字节的十六进制数:\n")
while(len(key)!=0):
key=bytes.fromhex(key)
desEncrypt(data=key)
key=input("\n\n请输入8个字节的十六进制数:\n")
标签:22,16,python,54,29,36,EDS,密钥,import 来源: https://blog.csdn.net/Alasding/article/details/117266883