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python编程快速上手-实践项目答案5

作者:互联网

Python编程快速上手第五章课后答案

好玩游戏的物品清单

字典值:

{'rope': 1, 'torch': 6, 'gold coin': 42, 'dagger': 1, 'arrow': 12}

写一个名为displayInventory()的函数,它接受任何可能的物品清单,并显示如下:

Inventory
1 rope
6 torch
42 gold coin
1 dagger
12 arrow
Total number of items: 62

代码如下:

stuff = {'rope': 1, 'torch': 6, 'gold coin': 42, 'dagger': 1, 'arrow': 12}
def displayInventory(items):
    print('Inventory')
    total_num = 0
    for k, v in items.items():
        print(str(v) + ' ' + k)
        total_num += v
    print('Total number of items: ' + str(total_num))


displayInventory(stuff)

列表到字典的函数,针对好玩游戏物品清单

写一个名为addToInventory(inventory,addedItems)的函数,其中inventory参数是一个字典,表示玩家的物品清单,addedItems参数是一个列表。
addToInventory()函数应该返回一个字典,表示更新过的物品清单。请注意,列表可以包含多个一样的项。
输出应如下:

Inventory
45 gold coin
1 rope
1 dagger
1 ruby
Total number of items: 48

代码如下:

dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']


def displayInventory(items):
    print('Inventory')
    total_num = 0
    for k, v in items.items():
        print(str(v) + ' ' + k)
        total_num += v
    print('Total number of items: ' + str(total_num))


def addToInventory(inventory, addedItem):
    for i in addedItem:
        if i in inventory:
            inventory[i] += 1
        else:
            inventory[i] = 1
    return inventory


inv = {'gold coin': 42, 'rope': 1}
dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']
inv = addToInventory(inv, dragonLoot)
displayInventory(inv)

标签:dagger,gold,python,items,编程,num,inventory,上手,coin
来源: https://blog.csdn.net/Jrieh/article/details/113379357